Question

f(x) = 3x + 2; g(x) = 3x - 5
Find f/g.
A.(f/g)(x) = Quantity three x minus five divided by three x plus two.; domain {x|x ≠ - Two over three. }
B. (f/g)(x) = Quantity three x plus two divided by three x minus five.; domain {x|x ≠ Five over three. }
C. (f/g)(x) = Quantity three x minus five divided by three x plus two; domain {x|x ≠ Five over three. }
D. (f/g)(x) = Quantity three x plus two divided by three x minus five; domain {x|x ≠ - Two over three. }

Answer 1

yikes

Answer 2

for real.. it's a headache

Answer 3

equation editor would help a great deal, but put one over the other

Answer 4

like \[\frac{3x+2}{3x-5}\] that is all

Answer 5

lol xD

Answer 6

oh i see you have another part, the "domain"

Answer 7

to find it, set \[3x-5=0\] and solve for \(x\)in two steps only
then say "all real numbers except that one"

Answer 8

let me know when you get it

Answer 9

im sorry, I don't get it I'm really confused

Answer 10

ok do you get the \[\frac{f}{g}\] part?

Answer 11

yes

Answer 12

ok so that is taken care of, good
now there is one more part, the "domain"
lets take it slow

Answer 13

you cannot "divide by zero" (i tired it once, had a headache for a week) which is the math teacher way of saying that the denominator of your fraction \(3x-5\) cannot be equal to zero
in practical terms what this means is that you have to solve the equation \[3x-5=0\] for \(x\)
do you know how to do that?

Answer 14

"no" is a fine answer, just asking

Answer 15

no..

Answer 16

ok lets do it

Answer 17

\[3x-5=0\] add 5 to both sides get \[3x=5\] then divide both sides by 3 to finish with \[x=\frac{5}{3}\]

Answer 18

like i said, two steps only
add 5, divide by 3
so your domain is all real numbers except \(x=\frac{5}{3}\)

Answer 19

ohhh okay

Answer 20

so it would be C?

Answer 21

@zepdrix

Answer 22

hello?