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Mathematics 15 Online
OpenStudy (iwanttogotostanford):

Fin

jhonyy9 (jhonyy9):

what say the sin. law ? do you know ?

jhonyy9 (jhonyy9):

sin B = ?

OpenStudy (sshayer):

\[\sin \angle=\frac{ opposite~ side }{ hypotenuse. }\]

OpenStudy (sshayer):

\[\tan \angle =\frac{ opposite ~side }{ adjacent~side ~but~\not~hypotenuse. }\]

OpenStudy (sshayer):

you are correct.

OpenStudy (iwanttogotostanford):

@sshayer

OpenStudy (sshayer):

\[ \pi~radians=180~ degree\]

OpenStudy (sshayer):

\[-\frac{ \pi }{ 3 }~radians=\frac{ -180 }{ 3 }=-60~degrees.\]

OpenStudy (iwanttogotostanford):

oh wow I get it thanks!

OpenStudy (sshayer):

yw

OpenStudy (sshayer):

because imaginary roots always occur in pairs. so 2 i is also a zero off(x) \[x= \pm 2i,\] hence x+2i and x-2 i are factors of f(x) \[\left( x+2 \iota \right)\left( x-2 \iota \right)=x^2-(2 \iota)^2=x^2-4 \iota ^2=x^2-4*-1=x^2+4\] divide f(x) by x^2+4 |dw:1472678197269:dw| \[x^2-9=x^2-3^2=(x+3)(x-3)\] x+3=0 gives x=-3 x-3=0 gives x=3 all zeros are \[\pm 2 \iota ,\pm 3\]

OpenStudy (iwanttogotostanford):

@sshayer

OpenStudy (iwanttogotostanford):

@retirEEd

OpenStudy (iwanttogotostanford):

@sweetburger @zepdrix

zepdrix (zepdrix):

\[\large\rm g(x)=-(x - 7)^2+1\]This is a quadratic, written in vertex form. Do you know where the vertex is located?

OpenStudy (iwanttogotostanford):

@campbell_st

zepdrix (zepdrix):

??

zepdrix (zepdrix):

Why do you ask for help and then ignore me?

OpenStudy (iwanttogotostanford):

Im sorry I was offline!

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