A bullet is fired into the air with an initial velocity of 1,200 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 2 seconds? (Neglect the resistance of air on the bullet. Round your answer to the nearest whole number.)
___ ft

Question

A bullet is fired into the air with an initial velocity of 1,200 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 2 seconds? (Neglect the resistance of air on the bullet. Round your answer to the nearest whole number.)
___ ft

liziekay · Answer

@zepdrix

campbell_st · Answer

so you know the horizontal acceleration is zero

integrating this you can find the horizontal velocity as 

$$v_{h} = Vcos(\alpha)$$

V = initial velocity   1200 ft/sec

the angle is 45 so you have 

$$v_{h} = 1200\cos(45)$$

if you integrate this equation with respect to time (t) you get the horizontal displacement equation. 

the initial condtions for the horizontal displacement seem to bet at t = 0, x = 0

then when you get the equation, just substitute t = 2 and evaluate