Can someone plz help me with this probability problem!! :D Will give medal :)
2. Create a probability distribution table for the following experiment. A coin is tossed two times and after each toss a head or tails is recorded. Let the discrete random variable represent the number of heads in the two tosses.
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satellite73 (satellite73):
a coin is tossed twice
there are \(2\times 2=4\) equally likely outcomes
not such a large number that we can't list them all \[\{HH, HT, TH, TT\}\]
satellite73 (satellite73):
what are the possible number of heads tossed?
OpenStudy (narusamisty):
4 times? :) but im not sure on how to graph it
satellite73 (satellite73):
whoa hold the phone
satellite73 (satellite73):
lets forget about a graph for a second
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satellite73 (satellite73):
you got two coins, and not that it makes any difference, lets say the first is a dime, the second a nickel
satellite73 (satellite73):
you toss them both
do you understand what i meant by \[\{HH, HT, TH, TT\}\] is the set of possible outcomes ?
OpenStudy (narusamisty):
sorry the HH,HT,TH,TT confused me
satellite73 (satellite73):
ok so lets say the first coin is a dime, the second in a nickel
then \(HT\) means the dime was Heads and the nickel was Tails
satellite73 (satellite73):
is it more clear now?
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OpenStudy (narusamisty):
nope im still confused :(
satellite73 (satellite73):
ok lets try with a picture
OpenStudy (narusamisty):
okay :)
satellite73 (satellite73):
satellite73 (satellite73):
do you understand that table?
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OpenStudy (narusamisty):
yes :)
satellite73 (satellite73):
ok so now you see there are four possible equaly likely outcome right? i just abbreviated them as \[\{HH, HT, TH, TT\}\]
OpenStudy (narusamisty):
so then it would be 3/4 of the possible number of heads tossed or am i still wrong? :)
satellite73 (satellite73):
ok now we got all possible outcomes, now lets see what the possible number of heads are in two rolls
OpenStudy (narusamisty):
okay
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satellite73 (satellite73):
start with \(HH\) how many heads?
OpenStudy (narusamisty):
1? :)
satellite73 (satellite73):
???
OpenStudy (narusamisty):
or is it 2? ._.
satellite73 (satellite73):
yes, 2
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satellite73 (satellite73):
so one possibility is you get two heads
how about \(HT\)?
OpenStudy (narusamisty):
1 right?
satellite73 (satellite73):
right m
satellite73 (satellite73):
and \(TH\)?
OpenStudy (narusamisty):
1 as well?
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satellite73 (satellite73):
yes
and finally \(TT\)
OpenStudy (narusamisty):
0 :)
satellite73 (satellite73):
yeah good
so if we have a random variable, usually denoted by \(X\) there are three possible values for \(X\) \[X=0,X=1,X=2\]
satellite73 (satellite73):
now for the distribution
\[X=0\] means you get no heads, i.e. two tails
how many ways are there to do that?
OpenStudy (narusamisty):
what do you mean how many are there to do that? :(
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satellite73 (satellite73):
there are four possible outcomes , abbreviated as \[\{HH, HT, TH, TT\}\]
out of those, how many are TT (it is a silly question kind of, since the answer is obvious)
OpenStudy (narusamisty):
ah it would be 1 :)
satellite73 (satellite73):
right
and since there are four equally likely outcomes, \[P(X=0)=\frac{1}{4}\]
satellite73 (satellite73):
now how many ways can you get \[X=2\]
OpenStudy (narusamisty):
3 times right? :)
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satellite73 (satellite73):
nope
satellite73 (satellite73):
how may tosses has two heads?
satellite73 (satellite73):
how many HH do you see in \[\{HH, HT, TH, TT\}\]
OpenStudy (narusamisty):
ohh ok i was thinking of the possible heads that i could get
OpenStudy (narusamisty):
it would also be 1
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satellite73 (satellite73):
right so \[P(X=2)=\frac{1}{4}\]
and finally how many ways can \(X=1\)?
OpenStudy (narusamisty):
does that go for the TH?
OpenStudy (narusamisty):
2? :)
satellite73 (satellite73):
yes
so \[P(X=1)=\frac{2}{4}\] which you want to reduce to say \[P(X=1)=\frac{1}{2}\]
OpenStudy (narusamisty):
okay :)
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OpenStudy (narusamisty):
now is it that i have to graph it? :)
satellite73 (satellite73):
how all we need to do is write the complete probability distribution which we already have \[P(X=0)=\frac{1}{4}, P(X=1)=\frac{1}{2}, P(x=2)=\frac{1}{4}\]
satellite73 (satellite73):
i don't know what the table is supposed to look like
satellite73 (satellite73):
you got an example?
OpenStudy (narusamisty):
yes wait a sec :)
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