Find the inverse: f(x)=2x-1/3
assuming it is \[\frac{2x-1}{3}\], solve \[x=\frac{2y-1}{3}\]for \(y\)
any idea how to do that?
no :(
ok could you do it with numbers ? solve for \(y\) \[\frac{2y-1}{3}=7\] for example
y=11?
i don't know, i didn't do it but the first step is to multiply both sides by 3, to get \[2y-1=3\times 7\]
then add one, get \[2y=22\] then divide by 2, get \(y=11\) so you are right
now lets repeat with variables, the procedure is the same
Would you please draw this equation, f(x)=2x-1/3, so that all involved here can be absolutely sure we're on the same wavelength?
\[\frac{2y-1}{3}=x\] first multiply both sides by \(3\)
Note that satellite73 had to ask for clarification, and I too wondered what you meant.
this symbol "/" means division :) @mathmale
As if I didn't know. But did you mean f(x)=2x-1/3 as in \[f(x)=2x-\frac{ 1 }{ 3 },\]
or did you mean f(x)=2x-1/3 as in \[f(x)=(2x-1)/3, or f(x)=\frac{ 2x-1 }{ 3 }?\]
\[f(x)=\frac{ 2x-1 }{ 3}\]
2x-1=3x
OK. Fine. In that case it is essential that y ou enclose "2x-1" inside parentheses, OR write your function as \[f(x)=\frac{ 2x-1 }{ 3 }\]
2x-1=3x ? Where did that come from?
close \[2y-1=3x\] is step one
next add 1 to both sides
alright.
Yes, but where did that come from? Please explain what you're doing.
2y-1+1=3x+1
Find the inverse of f(x)=2x-1/3. Note that you MUST write this as f(x)=(2x-1)/3. Next, replace f(x) with y: y=(2x-1)/3. What is the next step, given that you are to find the inverse of f(x)?
did you get to \[2y=3x+1\] yet?
yes
last step, divide by 2 which really means just write it
\[\frac{ 3x+1 }{ 2 }\]
bingo \[f^{-1}(x)=\frac{3x+1}{2}\]
notice that \[f(11)=\frac{2\times 11-1}{3}=7\] and \[f^{-1}(7)=\frac{3\times 7+1}{2}=11\] just as it should
Got it :)
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