Simplify (3a^2)^3 (2 and the last 3 are exponents) I just wanted to double check my answer to make sure I'm doing this correct. The answer would be: (6a)^6 Am I correct? Do the parenthesis need to be removed?
@sleepyjess @jabez177
@pooja195 @mathstudent55
@deltaforce209
32a2
So...after multiplying the 6 by the exponent 2 it needs to be multiplied by the exponent 6?
thats what i came up with so idk if i am on point correct but im pretty sure it is
You need to distribute the power of 3 into the equation.... \(\Large{(3^3a^{(2\times 3)})}\)
3a2 • 3 Step 2 : Multiplying exponents : 2.1 31 multiplied by 31 = 3(1 + 1) = 32 Final result : 32a2
So...I feel like I'm getting conflicting answers or I just don't see how one plays out right...
which one mine i asked my teacher so it should be right
Delta's sounds right...most of the time I just don't take it far enough and it's usually a much bigger number than what I came up with.
thank you
Its not quite right. You need to distribute the exponent 3 into the equation which having two exponent like in this equation would multiply them....
But what would that equal out to?
Yes it does... \(\LARGE{(3^{3}a^{(2\times 3)})}\) Try simplifying.
28a5? Or does the entire thing need to be multiplied by the exponent 5?
Wait, 27 not 28.
Almost there :) 2 by 3 actually equals 6 since we have 3+3 or adding 3 twice...so it simplify to... \(\LARGE{27a^{6}}\)
Oh shoot I read the x as a +. So it should be 27a6.
Yup :)
Okay, thank you! Both of you.
np :)
np
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