Question

Plz Help

2
1/2+(3/8−1/8)

Answer 1

@andrejrusa12

Answer 2

Do you mean this? \(\large \frac{1}{2} - 3(\frac{1}{2} +1) \)?

Answer 3

2 power at the end and yes

Answer 4

sooo... \(\large \frac{1}{2}-3(\frac{1}{2} +1)^2 \)?

Answer 5

yea idk how to write it like that but yes thats it

Answer 6

Follow "PEMDAS"

So first do what's in parentheses, which is \(\large (\frac{1}{2}+1) \). Do you know how to add them?

Answer 7

nope. idk how to add it like that

Answer 8

im guessing 1 1/2

Answer 9

Yess, but it would be easier to handle as a fraction.. to add them just convert the 1 into a fraction. 1 is the same as \(\large \frac{2}{2} \)

So \(\large \frac{1}{2}+\frac{2}{2} \)

Answer 10

3/2?

Answer 11

Yess, now, do you know how to do exponents?

Now we have to do the exponents which is \(\large \frac{1}{2}-3\color{red}{(\frac{3}{2})^2} \)

Answer 12

\(\large (\frac{3}{2})^2 \) is the same as \(\large \frac{3}{2}*\frac{3}{2} \) so just multiply them

Answer 13

i got no clue

Answer 14

1/2+(3/8−1/8)2

Answer 15

i figured the other 1 out can u help with this 1

Answer 16

\(\large \frac{1}{2}+(\frac{3}{8}-\frac{1}{8})^2 \)

Do the parentheses first, what do you get?

Answer 17

2/8

Answer 18

isnt that now.... 1/2+2/8 2

Answer 19

hello?

Answer 20

Right!

Now if you simplify that you get 1/4, which is easier to work with:
\(\large \frac{1}{2}+(\frac{1}{4})^2 \)

Now doing the exponent part, \(\large \color{red}{\frac{1}{4}^2} \)

\(\large \frac{1*1}{4*4} =\frac{1}{16} \)

\(\color{blue}{x^2=x*x} \)

Now just add them together -

\(\large \frac{1}{2}+\frac{1}{16} \)

Since they don't have common denominators, you'll need to find one, which would be \(\color{red}{16} \)

In order to get 16 from 2, you need to multiply by a common factor of 8 -

\(\large \frac{1}{2} *\frac{8}{8} =\frac{8}{16} \)

Now you can add them -

\(\large \frac{8}{16} +\frac{1}{16} \)

Answer 21

make sense?