Question

Geometry Help Please? Circles - Finding Radius and Center? Thanks.

Answer 1

This is the equation:
x^2 + 4x + y^2 − 6y = −4

Answer 2

\[x^2 + 4x + y^2 - 6y = -4\]
set it in the squared form
\[(x^2 + 4x) + (y^2 -6y) = 4\]
Now you will have to get the coefficent of the term with degree equal to 1 and divide it by 2 and then square it.
So the new shape would be
\[(x^2 + 4x +4) + (y^2 - 6y + 9) = 4 + 4 + 9\] (add the same to the other side)
Simplify
\[(x^2 + 4x + 4) + (y^2 - 6y + 9) = 17\]
Now change the shape
\[(x +2)^2 + (y - 3)^2 = \sqrt{17}\]
Center is (-2,3) radius is \[\sqrt{17}\]

Answer 3

Gosh that was tough lol.. any questions?

Answer 4

I'm sorry, but thank you so much!

Answer 5

No questions at the moment, but thanks!

Answer 6

you welcome :)

Answer 7

wait i love proving my answer so here...
Just to prove am right..

Answer 8

Okay, thanks. xD

Answer 9

\[x^2+y^2+2gx+2fy+c=0\]
center Is (-g,-f)
\[radius=\sqrt{g^2+f^2-c}\]