Question

Help me with physics/math

A ball is thrown directly downward from a bridge at 40 m/s

How much time does it take the ball to strike a river 110 meters below?

Answer 1

\[s=ut +\frac{ 1 }{ 2 }g t^2\]
110=40t +1/2 *9.8 1t^2
find t

Answer 2

Amplifying sshayer's equation:\[s=s _{0}+v _{0}t+\frac{ 1 }{ 2 }g t^2\]

s_0 is the initial height, v_0 is the initial velocity, t is time and g is acceleration due to gravity. since the problem presents quantities in the metric system, use \[g=-9.8\frac{ m }{ \sec^2 }\]

Answer 3

Your first step is to write the initial velocity correctly. Give this a try.

I would use the height of the bridge as the initial height of the ball, and s=0 as the height of the ball when it hits the water.

Please show your work. Ask questions.