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Mathematics 7 Online
OpenStudy (thatlilmathgirl12xd):

Is there a formula for situations like this?

OpenStudy (thatlilmathgirl12xd):

OpenStudy (thatlilmathgirl12xd):

@raffle_snaffle

OpenStudy (thatlilmathgirl12xd):

@zepdrix

OpenStudy (thatlilmathgirl12xd):

@Jadeishere

OpenStudy (thatlilmathgirl12xd):

@ShadowLegendX

OpenStudy (shadowlegendx):

Does it ask you to use a specific method?

OpenStudy (thatlilmathgirl12xd):

No it does not.

OpenStudy (shadowlegendx):

Do you have an idea on how to start with this problem?

OpenStudy (thatlilmathgirl12xd):

No I have no idea on how to start this problem.

OpenStudy (shadowlegendx):

Ok, well there are there are two methods. Elimination and Substitution.

OpenStudy (shadowlegendx):

\[x + 2y = 15\] \[x - 2y = -9\]

OpenStudy (shadowlegendx):

Elimination is the easiest one to do here, because of 2y and -2y canceling each other out. Basically we add these two equations. \[(x + 2y = 15) + (x -2y = -9)\]

OpenStudy (shadowlegendx):

We end up with \[2x = 6\]

OpenStudy (shadowlegendx):

Divide by 2 \[x = 3\]

OpenStudy (shadowlegendx):

Now we put 3 in for x, then solve for y

OpenStudy (thatlilmathgirl12xd):

Oh I see. That makes sense.

OpenStudy (shadowlegendx):

\[3 + 2y = 15\] \[2y = 12\] \[y = 6\]

OpenStudy (shadowlegendx):

Now we input both x and y into both equations to check our work

OpenStudy (thatlilmathgirl12xd):

We get x=3 and y=6

OpenStudy (shadowlegendx):

\[x + 2y = 15\] \[3 + 12 = 15\]

OpenStudy (shadowlegendx):

\[3 - 12 = 9\]

OpenStudy (shadowlegendx):

I gotta go, I hope this helped

OpenStudy (thatlilmathgirl12xd):

YAY! There is another question like this. I am going to solve it can you check it for me and make sure it is correct when you come back?

OpenStudy (thatlilmathgirl12xd):

Thanks a million! :-D

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