A proton enters a magnetic field of lux density 1.5 W b/m^(2) with a velocity if 2 x 10 ^(7) m/s at an angle of 30 degrees Celsius with the field. Compute the force on the proton.

Question

irishboy123 · Answer

you know this ${\mathbf  {F}}=q{\mathbf  {v}}\times {\mathbf  {B}} \, \hat n$ ???

for the magnitude
$ |\mathbf  {F}| =q{ |\mathbf  {v}} | \, |{\mathbf  {B}}| \sin \theta $

$q = 1.60217.....×10^{−19} C$

make sure you get $\theta $ right way round.  use the right hand rule if there is a drawing...