electricmagnetic waves? corona loss? semonila dipole?/ is there any pics of this??not sure what 1 it is but my profile pic is what im referiing to.. i cant find any phoyos of this online..

Question

osprey · Answer

If you could supply a bit more information about what sort of input you want. Input to you, would be output from, say, me. For me to give an output, I'd have to have a source of input. That's missing in this question. There's no pictures of the pictures you're talking about. http://perendis.webs.com

rummyjer · Answer

https://youtu.be/OMs0sPVDSdQ

rummyjer · Answer

Hope this helps . Thoughts??

osprey · Answer

I've just been thinking about what I think this question might be. Electric power lines carry electric current. It's long distance electrical power transmission, and so to keep the heat dissipation down, it is done at as low a current as is possible, and the associated high (kilovolts) voltage. There's a bit of help here from various transformers, to step down the high voltage at the consumer end, so that the consumer gets about 250V.
Now, given that you've got basically a long piece of wire, which is what the transmission line could be thought of as being, then the wire is carrying an ALTERNATING CURRENT, AC. And, that could make for a ELECTRIC DIPOLE AERIAL, or antenna. And that could make for electromagnetic radiation, much the same way that any radio broadcaster broadcasts their (mostly drivel) information.
This is a guess based on the words electric dipole in the posting. Also "coming off" as in BEING BROADCAST, possibly ??? How you'd get images of that, I don't know, but I guess that the youtube link may give a clue. 
Any still pictures or other diagrams or other information would help.

osprey · Answer

Another bit o thinking ... Assuming that we are talking about AERIALS here, then the length of an aerial is related to the frequency of the AC in it. Basically, the lower the frequency the longer the aerial. The higher the frequency, the shorter the aerial. So, a good old power line carrying at 50 cycles/second - a low frequency - might be long enough to broadcast an electromagnetic wave. It would then be picked up as interference by any device which could detect it, I think.

osprey · Answer

OK, I've just seen the photo of what seems to be a power line with an arc of light near it. I don't know what the dimensions are in the photo, but that looks to me remarkably like a diagram of a STANDING WAVE, such as you'd maybe find in any boring old UK A level physics text  book in either waves, sound, or electromagnetism. 
BUT there's a question, as you, I think are trying to ask. What makes the arc visible ? I'd have to take another guess that it's an electrical discharge of the various atoms in the atmosphere which are along the line of the standing wave. A bit like dust piles up at nodes on a vibrating plate.

rummyjer · Answer

https://plus.google.com/105813225250184048294/posts/HGozoCNJAhj

osprey · Answer

After all, what is lightning. A very highly charged cloud decides to discharge to earth. It does so by flinging a massive pulse of electricity through the atmosphere. That pulse energises the atoms in the atmosphere, and when they "de energise" so to speak, you get visible light. Enough of the atoms doing this trick, and you get a spectacular bit of visible light. Add to that the enormous CRACK as the air expands near the discharge, and you've got THUNDER. 
And, there was, it seems a greek god called Thor, who was the god of thunder, so they took it fairly seriously.

osprey · Answer

I've not checked this, but as I recall one of the pictures, it shows a pile of blobs, with a sort of spike in the middle. That would fit with the node=blobs, antinode=spike notion of the transmission line radiating at about 50Hz. If you had a long stretched string, such as a violin string, or just a taught bit of string or wire which was clamped at both ends and you plucked the thing in the centre, it would vibrate at the centre, but not at the points where it was clamped. The centre is the antinode, the clamped points are the nodes. If you took a snapshot picture of this, you'd probably see an arc depending on where abouts in the standing wave oscillation sequence you happened to take the photo.

osprey · Answer

Help me out on this one ... I keep reading "semonila" as "semolina" ... can anyone offer me "tea and sympathy", or maybe a drink, or maybe a shrink ? (the difference starts from the fifth letter of each word ... is that a good excuse ? and they're anagrams, aren't they ... )
Osprey back to nest ?