Is this correct?
What would be the volume in liters of an ideal gas, if a 0.425 mole sample of the gas had a temperature of 900 degrees Celsius at a pressure of 3.00 atmospheres? (The ideal gas constant is 0.0821 L•atm/mol•K.) 10.468 L 13.643 L X 28.471 L 40.929 L
@sweetburger
@phi @pooja195 @Loser66 @whpalmer4 @sammixboo @AloneS @kidrah69
off-hand, I don't remember the details of the gas law. what formula do you use ?
900*C = 1173 K 3.00atm = 303.98kPa pV = nRT V = (nRT)/p = (0.425 x 8.31 x 1173)/303.98 = 13.629L
That's how I got the answer ^^^
yes, that looks good.
Okay, thanks!
but I'm not sure why you changed to kPa?? n is in units of L*atm/(mol*K) so the calculation is \[ V= 0.0821 \frac{ L \ \cancel{atm}}{\cancel{mol} \ \cancel{K}} \cdot 0.425 \cancel{mol} \cdot 1173 \cancel{K}\cdot \frac{1}{3 \cancel{atm}}\]
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