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Algebra 7 Online
OpenStudy (chaz03):

2+1/7x = 4

OpenStudy (photon336):

I would take care of the addition first. \[\frac{ (2+1) }{ 7x} = 4 \] \[\frac{ 3 }{ 7x} = 4 \] follow?

OpenStudy (chaz03):

ok

OpenStudy (chaz03):

i got you

OpenStudy (photon336):

alright, we need to get x by itself

OpenStudy (chaz03):

k

OpenStudy (photon336):

\[\frac{ 3 }{ \cancel\7\cancel\x}*(\frac{\cancel\7\cancel\x }{ 1 }) = 4 *(7x)\] \[3 = 28x \]

OpenStudy (photon336):

how would we solve for x now?

OpenStudy (chaz03):

um that last one i could not follow yo on

OpenStudy (photon336):

oh so I multiplied both sides by 7x

OpenStudy (photon336):

7x canceled out on the left side

OpenStudy (chaz03):

oh gotcha

OpenStudy (chaz03):

divide 28 from both sides

OpenStudy (chaz03):

sooooo

OpenStudy (photon336):

what is x ?

OpenStudy (chaz03):

one sec

OpenStudy (chaz03):

9.3

OpenStudy (chaz03):

i think

OpenStudy (photon336):

let's check that

OpenStudy (chaz03):

it wasen't right

OpenStudy (photon336):

\[3 = 28x \] \[\frac{ 3 }{ 28 } = x \]

OpenStudy (photon336):

so you needed to get x by itself

OpenStudy (photon336):

to get x by itself you would divide both sides by 28 follow?

OpenStudy (chaz03):

right

OpenStudy (photon336):

maybe try a similar type of problem and work it out (2+2)/3x = 5

OpenStudy (mathmale):

You may have to use parentheses to convey the original problem correctly. Which of the following did you mean? 2 + (1/7)x = 4 2 + 1 / (7x) = 4 These are quite different.

OpenStudy (chaz03):

2 + (1/7)x = 4

OpenStudy (photon336):

hm yeah in that case it's different

OpenStudy (mathmale):

Photon: I see the same ambiguity in your post. Please clarify your measing, using parentheses.

OpenStudy (chaz03):

whoops

OpenStudy (mathmale):

So, what was the original question?

OpenStudy (mathmale):

|dw:1473021290007:dw|

OpenStudy (chaz03):

i still need x

OpenStudy (mathmale):

|dw:1473021309971:dw|

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