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satellite73 (satellite73):
the one half in the exponent means take the square root
OpenStudy (alexh107):
The answer in the back says it's -5. I don't understand how to get that. So it would be\[\sqrt{-9}\]
satellite73 (satellite73):
\(-5\) is not possible,. perhaps you are looking at the wrong numbered problem
in any case it is not \[\sqrt{-9}\] but rather \[-\sqrt9\] the minus sign is out fron
OpenStudy (alexh107):
My bad, it's -3 in the book.
satellite73 (satellite73):
yes that is right
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OpenStudy (alexh107):
Wouldn't it be a +/- 3i or something?
satellite73 (satellite73):
no it would not
lets look at a simpler example
satellite73 (satellite73):
what is \[100-5^2\]?
OpenStudy (alexh107):
75?
satellite73 (satellite73):
yes because \[100-5^2=100-25=75\]
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satellite73 (satellite73):
now what is \[-5^2\]?
OpenStudy (alexh107):
-25
satellite73 (satellite73):
right
satellite73 (satellite73):
notice that the minus sign stays right out front, since what is beings squared is \(5\) not \(-5\)
satellite73 (satellite73):
now consider \[-9^{\frac{1}{2}}\] what are you taking the square root of?
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OpenStudy (alexh107):
-9
OpenStudy (alexh107):
Oh wait, 9?
satellite73 (satellite73):
right
OpenStudy (alexh107):
So the square root of 9 is three and then you add the - sign so it's -3?
satellite73 (satellite73):
just like \[-5^2=-5\times 5=-25\] the exponent is for the \(5\) not \(-5\)
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satellite73 (satellite73):
yes exactly
the square root of nine is three and the minus sign stays there