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Mathematics 12 Online
OpenStudy (will.h):

Algebra ll Help..Medal,Fan...

OpenStudy (will.h):

@ganeshie8 hi can you help Both 4 and 5

OpenStudy (will.h):

@Kainui

OpenStudy (will.h):

@mathmate

OpenStudy (will.h):

here's what i know so far: we know that the number of visitors increase exponentially as the temperature increase and linear represent the people who leave the zoo so if we subtract both equations/functions from each other we would get the number of people at the zoo at a specific temperature

OpenStudy (will.h):

Thank you @NvidiaIntely

OpenStudy (will.h):

@mathmale

OpenStudy (ben_allen):

GG

OpenStudy (mathmale):

You'll need to come up with models that reflect what's happening here. Let n represent the number of visitors. n depends exponentially on the temperature, T, so n=f(T) = ke^T (which is an exponential function). Let L(T) represent the number of people who leave the park early. This is NOT the same as n(t), the number of park visitors. Function L(t) is linear, and thus its form must be L(T)=mT. This states that if the temperature increases, the number of people, L, leaving the park early is a constant times the temperature, T. Think these thru. Do they make sense to you? If not, explain why. Questions?

OpenStudy (will.h):

Yeah looks terrific we can subtract the number of people leaving the zoo from the number of people entering the zoo to get the total amount of people in the zoo at a specific temperature. So lets say the exponential part of the attendance can be modeled by the following \[f(t)=a*b^(t−h)+k\] t - h is the power. Then we have to subtract the linear part g(t)=mt+c because we are losing attendance. So the final result would be: P(t)=(a⋅b^(t−h)+k)−(mt+c) where P stands for population in the zoo at temperature t. is that correct? am i missing anything?

OpenStudy (will.h):

for the question 5 i wrote this we can find the inverse of an exponential function by following the steps below: 1- we have to change f(x) into y 2- we have to switch the x and y variables. 3- we have to solve for y 4- after solving for y name it f^-1(x) After finding the inverse function we have to substitute x = 250 to find the needed value. Is that enough

OpenStudy (mathmale):

Assuming that these two models are correct (which is not a given), we are to look for a way to combine these two equations into one. One way of doing that would be to eliminate the variable T. That requires that we solve one or the other equation for T. I would start with n=f(T) = ke^T. Applying the ln operator to both sides of this equation results in ln n = ln k + T, which is similar to your result.

OpenStudy (mathmale):

I'd then substitute ln n-ln k = T for T in the other equation.

OpenStudy (will.h):

just like solving systems of equation? interesting. so mine was wrong?

OpenStudy (mathmale):

I agree that we could interpret P as the net number of park visitors. But I eventually solved for temperature, T, so your result and mine differ: yours has tempoerature T, whereas mine does not. How do we resolve this conflict?

OpenStudy (mathmale):

Looks like you've moved on to Question 5, whereas I'm still on Question 4. One at a time, please. ;)

OpenStudy (will.h):

okay well you tell me :) and sorry for moving to Q5

OpenStudy (mathmale):

We've been discussing four variables: T, P, n and L. We'll have to eliminate 2 of those to obtain a function with one dependent variable and one independent variable. Have you thought of this?

OpenStudy (mathmale):

You have introduced the function f, which means we have 5 variables floating around in the swimming pool. Again, we've got to cut the number of variables via elimiination. Which ones would you personally choose to eliminate, and why?

OpenStudy (will.h):

so to make this clear lets type in the functions we have already

OpenStudy (mathmale):

I doubt that there's just one unique "answer" to Question 4. We have the prerogative of eliminating whichever variable or variables we choose, to obtain a function representing whatever we choose it to represent. You mentioned "net number of visitors in attendance," which I believe is an achievable goal.

OpenStudy (mathmale):

Please review our discussion. Copy and paste each function you recognize. Then we can analyze what we have.

OpenStudy (will.h):

\[f(T) = ke^T\] \[L(t) = mt\]

OpenStudy (mathmale):

If we let P represent the number of visitors in attendance, and if we let T represent temperature, which component functions would make up the function P(T)?

OpenStudy (mathmale):

How would we define P(T) using the other functions we've derived or identified?

OpenStudy (mathmale):

Regarding your\[n=f(T) = ke^T\]

OpenStudy (mathmale):

and your \[L(t) = mt:\]

OpenStudy (will.h):

aren't we suppose to have 2 functions? 1 exponential and the other linear? This is getting confusing we had 3 now

OpenStudy (mathmale):

Please describe what each represents and make sure you and I are using the same variable to represent the same thing. For example, I used n(T) to repr. the number of visitors in attenance, whereas it seems you've used f(T). Please develop the function P(T), which represents the net number of visitors as a function of time, T.

OpenStudy (will.h):

So this would be a linear function correct? P(t) = st where p(t) is number of people who leave at certain t temperature

OpenStudy (mathmale):

Please define any new variables or constants you use (such as "s"), and please stick with my L(T) to represent the number of people leaving at temperature T. Adding new vars or consts. complicates the issue, doesn't it?

OpenStudy (will.h):

okay so L(t) = st s would be the slope which is also the change

OpenStudy (will.h):

is that correct?

OpenStudy (mathmale):

Not so much correct as acceptable; my function for the same purpose was L(T)=mT. There is no advantage here to substituting t for T or s for m. It's your homework, so please choose one version of this function and totally eliminate the other one, for the sake of simplicity.

OpenStudy (will.h):

Lol, So are we set to L(T) = mT? Now what do i do am as confused as you are

OpenStudy (will.h):

we have to set the exponential function now correct?>

OpenStudy (will.h):

and then ?

OpenStudy (will.h):

i know teaching can be awful lol bare w me

OpenStudy (mathmale):

I'm not confused, Will, I'm just asking you not to introduce new constants and variables unless you simultaneously get rid of the old ones permanently. Again, it seems that our goal is to develop a function P(T) that represents the NET number of visitors at the park as a function of temperature T (not t). It seems to me, then, that this function would look like P(T_= mT + (exponential part). You give that a stab, please.

OpenStudy (mathmale):

Review our entire discussion. Haven't we already come up with a function representing the exponential part?

OpenStudy (will.h):

we have this is the one f(T)=ke^T

OpenStudy (will.h):

to get this clear and walk step by step T is temperature and k is?

OpenStudy (mathmale):

k is a constant coefficient, just as m is a constant coeff in L(T)=mT. You weren't asked to find k, but should insert it as a placeholder.

OpenStudy (will.h):

great. Now what you want me to do? Do we subtract the exponential function from the linear?

OpenStudy (mathmale):

I mean, should insert the constant coeff as just "k"

OpenStudy (mathmale):

Let me play the devil's advocate. Why would you subtract?

OpenStudy (mathmale):

We're talking about what Will wants to and has to do, not about what mathmale wants Will to do. ;)

OpenStudy (will.h):

Amazing question! Because if we subtract them from each other we would get the number of people at the Zoo at a certain temperature T Lol and MathMale i love you you're the best

OpenStudy (mathmale):

Thank you. Love you too, for your persistence and obvious good preparation. Exactly. if you subtract the expo. comp. from the linear comp., you'll have a formula for the net number of zoo visitors. Excellent.

OpenStudy (will.h):

Fabulous! So now ke^T - mT So the new function we can name it as S(T) = ke^T - mT i don't think we can somplify any further can we?

OpenStudy (will.h):

@mathmale you not leaving me are you? Leaving a man behind is a sin lol

OpenStudy (mathmale):

A sin? I repent. I also bow at your feet and thank you from the depths of my heart for the lovely testimonial.

OpenStudy (mathmale):

and repent again.

OpenStudy (will.h):

Lool i love you 2x now

OpenStudy (will.h):

don't solve for x lol

OpenStudy (mathmale):

One way to double check on the correctness of your result would be to test it to ensure that the result is positive. We wouldn't want to end up with a net of -247 visitors, would we? Or are we living on a different planet than the rank and file?

OpenStudy (mathmale):

I'll rewrite that in terms of z and solve for z, with your leave, of course.

OpenStudy (mathmale):

I'm not saying your answer is wrong! I'm just urging you to check that its range is positive, not zero or negative.

OpenStudy (will.h):

Yeah i hear you well. So The answer was S(T) = ke^T - mT if we have the Temp = 86 you said k is constant so can it be 6? and m is also constant so 4 and what about e?

OpenStudy (mathmale):

I'm grieving for that poor P we were discussing. Seems as tho' you've abandoned it in favor of S(T). How sad. We have several different unknown constants and one unknown variable here, so it may not be realistic for you to try to obtain a specific S(T) value. I'd suggest you can safely rest on your laurels now that you've gotten a new function based upon the given data, even if you don't have spec. values for the constants.

OpenStudy (mathmale):

Mind moving on to #5?

OpenStudy (will.h):

Sure let's role

OpenStudy (mathmale):

Role? Am I your role model, or your roll model, neither or both?

OpenStudy (will.h):

Lol am a model you're my math model <3

OpenStudy (mathmale):

I'm fat, so if you were to roll me out, the remains of me would be very wide.

OpenStudy (will.h):

Loool Just like the exponential growth? a math joke lol math jokes seem funny

OpenStudy (mathmale):

On the other hand, if I'm your role model, then my head (alone) might expand a bit much.

OpenStudy (will.h):

i wouldn't wonder! you have many info in that head so it has to expend lol

OpenStudy (mathmale):

Your prerog.: choose a variable to represent the number of pairs of jeans this guy owns. I promise not to toss it out and replace it with another variable that I like better.

OpenStudy (will.h):

Lool 13?

OpenStudy (will.h):

No variable omg S

OpenStudy (will.h):

wait i can see why you choose the variable M everytime.. MathMale double M ... hmm

OpenStudy (mathmale):

Actually, our friend Lon has already come up with a name: It's f (also written as f(t). So neither 13 nor omg S apply here. ;(

OpenStudy (mathmale):

(review question #5)

OpenStudy (mathmale):

So f(t) represents the number of jeans that our other friend, Tim, owns, as a function of time.

OpenStudy (will.h):

right so f(x) and it is exponential function and they want the inverse

OpenStudy (mathmale):

(who cares?)

OpenStudy (mathmale):

Let's mock up f(t) first. Agreed: f(t) is an expo fn. So, what would your model look like?

OpenStudy (will.h):

Lol okay so if we have function f(t) i would 1st change the name f(t) to y because that name kinda ugly

OpenStudy (mathmale):

Your indept. var. must be t (representing time). There must be a constant of proportionality. OK, so long as you take notes reminding yourself that the original function name was f. Sure, the first step to finding the inverse of a function f(t) is to replace f(t) with 'y.' Way to go, man.

OpenStudy (mathmale):

So, let's see your proposed model for f(t). It's an expo function, remember?

OpenStudy (will.h):

yeah

OpenStudy (mathmale):

So...

OpenStudy (will.h):

you want me to say the 2nd step or ?

OpenStudy (mathmale):

Nope. i want you to come up with an appropriate model for an expo. growth function.

OpenStudy (will.h):

okay leave that to me Mr

OpenStudy (mathmale):

You don't yet have a function, so it's too early to try to find the inverse . Mr. Goldmann.

OpenStudy (mathmale):

So, your lovely creation is the function f(t) = ?????? which is an expo function

OpenStudy (will.h):

wait why don't you handle that Lool .. So do you want the function in the exponential form like p* 1 + r)^x or ab^x? you pick

OpenStudy (mathmale):

Nope, I asked you first, so you're stuckw ith the task. You did fine in the previous question...you knew how to develop a model for expo grth.

OpenStudy (mathmale):

I pick? Why me?

OpenStudy (will.h):

okay f(t) = 2^t

OpenStudy (mathmale):

the first possibility you listed has connections to compound interest and other applications. No you won't. Question: Why have you chosen the base 2 for your expo function?

OpenStudy (will.h):

it can't be 1 because then it will be linear and 2 is growth so why not

OpenStudy (will.h):

Uhm silence makes me question my whole math skills lol

OpenStudy (mathmale):

2 would work, actually. But why 2? From our previous problem (#4), n=f(T) = ke^T There we used the base e, which is one of the most commonly used bases, most general, and applicable here.

OpenStudy (mathmale):

No reason for you to question your whole set of math skills! You're doing fine, actually. Give and take is important. Want this to be both instructive and fun for you.

OpenStudy (will.h):

yeah absolutely i love learning so tell me the reason of 2

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