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OpenStudy (will.h):

Algebra ll B Question

OpenStudy (will.h):

i am not sure about this one can the answer be that short really?

OpenStudy (will.h):

@kittiwitti1 @pooja195

OpenStudy (jonathan34):

answers?

OpenStudy (jonathan34):

hello?

OpenStudy (jonathan34):

@will.h

OpenStudy (jonathan34):

well bye

OpenStudy (will.h):

@jonathan34 i was away you know how to solve that?

OpenStudy (jonathan34):

ok back

OpenStudy (jonathan34):

i think i do

OpenStudy (will.h):

shoot

OpenStudy (jonathan34):

answers?

OpenStudy (will.h):

just tell me if my answer right or wrong and if wrong what's the right and if neither then what should i add to make it correct

OpenStudy (jonathan34):

ok np

OpenStudy (jonathan34):

give me your answer please

OpenStudy (jonathan34):

what grade?

OpenStudy (will.h):

OpenStudy (will.h):

@kittiwitti1 help dude

OpenStudy (jonathan34):

looks ok but you know the meaning of X?

OpenStudy (kittiwitti1):

I was here but I left... I mean I did respond to your request on your other question. And I'm not a dude, lol

OpenStudy (will.h):

yeah i know everything i just can't beleve the asnswer is that short

OpenStudy (jonathan34):

looks tricky right? lol

OpenStudy (will.h):

@kittiwitti1 Lol sorry

OpenStudy (jonathan34):

i cant find nothing wrong with it

OpenStudy (will.h):

okay i have couple more you think you can help?

OpenStudy (jonathan34):

well you did the fraction but...... what the answer you never but it?

OpenStudy (jonathan34):

ok

OpenStudy (jonathan34):

what grade is these looks so familiar

OpenStudy (will.h):

Algebra ll Part B i hate it

OpenStudy (jonathan34):

:O idk lol

OpenStudy (jonathan34):

@Vuriffy

OpenStudy (jonathan34):

@misty1212

OpenStudy (will.h):

Thanks for trying

OpenStudy (victoryisminehaha):

@jonathan34 may u come and help me after ur done?

OpenStudy (jonathan34):

ok bye will that was to hard for me

OpenStudy (jonathan34):

still with the same question lmaf lol

OpenStudy (jonathan34):

idk it good luck

OpenStudy (will.h):

Thanks

OpenStudy (will.h):

@mathmale

OpenStudy (jonathan34):

@marvin456 @misty1212 @MonkeyAGF @michaelschmidt @Atsie

OpenStudy (jonathan34):

these ppl will help

OpenStudy (jonathan34):

peace

OpenStudy (will.h):

Thanks @jonathan34

OpenStudy (will.h):

Hi Mathmale to avoid confusion let's start With Tommy question

OpenStudy (will.h):

i was just gonna tag you lol

OpenStudy (will.h):

So Math male let's make this quick and smooth i have 2 modules to finish and deadline is 3 days from now lol

OpenStudy (mathmale):

Hello, Will! I'd much prefer to focus on YOUR question and work with this Tommy separately and later.

OpenStudy (will.h):

Okay i will do the other lessons what time will you be on

OpenStudy (mathmale):

You have probably seen functions that look like this:\[A=P(1+r)^t\] Look familiar? can you remember what this formula is for?

OpenStudy (will.h):

Yeah when calculating the interest and all that it is exponential function

OpenStudy (mathmale):

sorry, we have a misunderstanding here. I didn't recognize the name Tommy, so did not realize you were discussing the problem at hand.

OpenStudy (mathmale):

correct: That's an exponential function, for compound interest.

OpenStudy (will.h):

Lool Mathmale i like how you think deeply

OpenStudy (mathmale):

It's great to be liked!

OpenStudy (will.h):

Are we solving Tommy or Tony?

OpenStudy (mathmale):

Look at \[A=P(1+r)^t\]

OpenStudy (mathmale):

and identify what P represents.

OpenStudy (will.h):

P is the principal normally and it is the initial number

OpenStudy (mathmale):

Just "principal." No "initial number." Right you are. The rest of that function is an exponential, correct?

OpenStudy (will.h):

yes

OpenStudy (mathmale):

Which math operation was performed on P and on (1+r)^t to obtain P(1+r)^t?

OpenStudy (will.h):

multiplication

OpenStudy (mathmale):

Yes. But in your response to this question, you've chosen addition instead of mult.

OpenStudy (will.h):

i don't understand what problem are we solving

OpenStudy (mathmale):

Think: what specifically does h(t)=350 represent?

OpenStudy (will.h):

that's the money he has and i chose multiplication because there would be the total money after interests

OpenStudy (will.h):

sorry addition i mean

OpenStudy (mathmale):

Multiplication is the correct operation, but your response used addition. Why would addition be correct instead of mult.?

OpenStudy (mathmale):

In the familiar formula\[A=P(1+r)^t\] do you see P being added to the expo function or multiplied by the expo function?

OpenStudy (will.h):

Correct it is multiplied but i thought that we would add the functions to get the total profit i didn't thought of it as both functions multiplied that's genius because p is indeed represent the investment he has

OpenStudy (mathmale):

Right. h(x) = P here, and both represent the initial amount of money Tommy has.

OpenStudy (mathmale):

So, toss out the ADDITION and substitute MULT. as you work on the given problem.

OpenStudy (will.h):

\[m(x) = 350(1.04)^(x-1)\]

OpenStudy (mathmale):

Yes. I'd start out by writing \[m(x) = h(x)*s(x) \]

OpenStudy (mathmale):

and then subst. $350 for h(x) and \[(1.04)^{x-1}\]for s(x).

OpenStudy (will.h):

so the last thing to say is the expression i wrote correct?

OpenStudy (mathmale):

If you agree, please explain what quantity this new function m(x) represents.

OpenStudy (will.h):

the interest is growth clearly and x is time and p is 350

OpenStudy (mathmale):

Unfortunately not, Will. I'm looking at your initial response, which included addition instead of mult. Please type out the new version of your response.

OpenStudy (mathmale):

The name of this function is "compound amount." You invest principal P (or h(x)) up front and leave the funds ini the bank for x years. The result is the AMOUNT you will have accumulated over x years; that includes both principal and interest.

OpenStudy (will.h):

okay here's the new response We have to multiply both functions to create a function that represent the total profit after x time \[m(x) = h(x) * s(x) \] \[m(x)=350(1.04)^(x−1)\]

OpenStudy (mathmale):

Please note that the commonest form of this formula for compound amount is \[A=P(1+r)^t\]

OpenStudy (mathmale):

I frankly do not know why the exponent in the given problem is x-1.

OpenStudy (will.h):

me neither i was gonna ask you why tho

OpenStudy (mathmale):

Why do you use the word "profit" here, when it's not mentioned in the orig. probl.?

OpenStudy (will.h):

because it would be profit investing is making profit after all

OpenStudy (mathmale):

the correct term is "compound amount." You invest principal P for x years, and A represents the amount, incl principal and interest, that you would have at the end of x years. It will save you a lot of trouble if you stick strictly to the definitions of words such as "profit," "amount," "principal," etc. Do not make up or borrow other words to use. P

OpenStudy (mathmale):

Profit in business has a whole different meaning: It's the difference between the revenue ($ taken in when something is sold) and the costs (the $ you have to spend to run your business).

OpenStudy (will.h):

That's smart i'd go with compound principal then

OpenStudy (mathmale):

More precisely, P(x) = R(x) - C(x): Profit is the difference of revenue and costs: Subtract costs from revenue. NO bearing on the problem at hand. And sorry, not compound principal; you mean "compound amount" when interest is compounded periodically.

OpenStudy (mathmale):

Don't get mad if I suggest you write down these terms and make certainl you can define them correctly.

OpenStudy (will.h):

Lol No that's just Smart to know the right terms i don't think teachers focus on it much but yeah it would be better to use the right ones

OpenStudy (mathmale):

So, once again (a quiz for you): Explain in words the name and purpose of \[A(x)=P(1+r)^x\]

OpenStudy (mathmale):

Review our discussion before you respond.

OpenStudy (will.h):

p is the principal r is the rate of either growth or decay and x is time and A(x) would be the compound amount

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