Algebra ll B Question
i am not sure about this one can the answer be that short really?
@kittiwitti1 @pooja195
answers?
hello?
@will.h
well bye
@jonathan34 i was away you know how to solve that?
ok back
i think i do
shoot
answers?
just tell me if my answer right or wrong and if wrong what's the right and if neither then what should i add to make it correct
ok np
give me your answer please
what grade?
@kittiwitti1 help dude
looks ok but you know the meaning of X?
I was here but I left... I mean I did respond to your request on your other question. And I'm not a dude, lol
yeah i know everything i just can't beleve the asnswer is that short
looks tricky right? lol
@kittiwitti1 Lol sorry
i cant find nothing wrong with it
okay i have couple more you think you can help?
well you did the fraction but...... what the answer you never but it?
ok
what grade is these looks so familiar
Algebra ll Part B i hate it
:O idk lol
@Vuriffy
@misty1212
Thanks for trying
@jonathan34 may u come and help me after ur done?
ok bye will that was to hard for me
still with the same question lmaf lol
idk it good luck
Thanks
@mathmale
@marvin456 @misty1212 @MonkeyAGF @michaelschmidt @Atsie
these ppl will help
peace
Thanks @jonathan34
Hi Mathmale to avoid confusion let's start With Tommy question
i was just gonna tag you lol
So Math male let's make this quick and smooth i have 2 modules to finish and deadline is 3 days from now lol
Hello, Will! I'd much prefer to focus on YOUR question and work with this Tommy separately and later.
Okay i will do the other lessons what time will you be on
You have probably seen functions that look like this:\[A=P(1+r)^t\] Look familiar? can you remember what this formula is for?
Yeah when calculating the interest and all that it is exponential function
sorry, we have a misunderstanding here. I didn't recognize the name Tommy, so did not realize you were discussing the problem at hand.
correct: That's an exponential function, for compound interest.
Lool Mathmale i like how you think deeply
It's great to be liked!
Are we solving Tommy or Tony?
Look at \[A=P(1+r)^t\]
and identify what P represents.
P is the principal normally and it is the initial number
Just "principal." No "initial number." Right you are. The rest of that function is an exponential, correct?
yes
Which math operation was performed on P and on (1+r)^t to obtain P(1+r)^t?
multiplication
Yes. But in your response to this question, you've chosen addition instead of mult.
i don't understand what problem are we solving
Think: what specifically does h(t)=350 represent?
http://assets.openstudy.com/updates/attachments/57cec1dbe4b0948881946eac-will.h-1473167871221-5.png
that's the money he has and i chose multiplication because there would be the total money after interests
sorry addition i mean
Multiplication is the correct operation, but your response used addition. Why would addition be correct instead of mult.?
In the familiar formula\[A=P(1+r)^t\] do you see P being added to the expo function or multiplied by the expo function?
Correct it is multiplied but i thought that we would add the functions to get the total profit i didn't thought of it as both functions multiplied that's genius because p is indeed represent the investment he has
Right. h(x) = P here, and both represent the initial amount of money Tommy has.
So, toss out the ADDITION and substitute MULT. as you work on the given problem.
\[m(x) = 350(1.04)^(x-1)\]
Yes. I'd start out by writing \[m(x) = h(x)*s(x) \]
and then subst. $350 for h(x) and \[(1.04)^{x-1}\]for s(x).
so the last thing to say is the expression i wrote correct?
If you agree, please explain what quantity this new function m(x) represents.
the interest is growth clearly and x is time and p is 350
Unfortunately not, Will. I'm looking at your initial response, which included addition instead of mult. Please type out the new version of your response.
The name of this function is "compound amount." You invest principal P (or h(x)) up front and leave the funds ini the bank for x years. The result is the AMOUNT you will have accumulated over x years; that includes both principal and interest.
okay here's the new response We have to multiply both functions to create a function that represent the total profit after x time \[m(x) = h(x) * s(x) \] \[m(x)=350(1.04)^(x−1)\]
Please note that the commonest form of this formula for compound amount is \[A=P(1+r)^t\]
I frankly do not know why the exponent in the given problem is x-1.
me neither i was gonna ask you why tho
Why do you use the word "profit" here, when it's not mentioned in the orig. probl.?
because it would be profit investing is making profit after all
the correct term is "compound amount." You invest principal P for x years, and A represents the amount, incl principal and interest, that you would have at the end of x years. It will save you a lot of trouble if you stick strictly to the definitions of words such as "profit," "amount," "principal," etc. Do not make up or borrow other words to use. P
Profit in business has a whole different meaning: It's the difference between the revenue ($ taken in when something is sold) and the costs (the $ you have to spend to run your business).
That's smart i'd go with compound principal then
More precisely, P(x) = R(x) - C(x): Profit is the difference of revenue and costs: Subtract costs from revenue. NO bearing on the problem at hand. And sorry, not compound principal; you mean "compound amount" when interest is compounded periodically.
Don't get mad if I suggest you write down these terms and make certainl you can define them correctly.
Lol No that's just Smart to know the right terms i don't think teachers focus on it much but yeah it would be better to use the right ones
So, once again (a quiz for you): Explain in words the name and purpose of \[A(x)=P(1+r)^x\]
Review our discussion before you respond.
p is the principal r is the rate of either growth or decay and x is time and A(x) would be the compound amount
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