Use the definition of the derivative f'(x)=lim h->0 f(x+h)-f(x)/h to find f'(x) where f(x)=x^2+x
Your function is f(x) = x^2 + x. Please find \[f(x+ \Delta x)\]
Then write out and simplify the difference quotient, \[\frac{ f(x+ \Delta x)-f(x) }{ \Delta x}\]
Finally, let that delta x go to zero. The result is your derivative, f '(x).
You can, of course, use "h" instead of "delta x."
would it be [(x+h)^2+(x+h)]-x^2+x/h?
would the answer be 2x?
@mathmale
f '(x) = 2x plus an integer. Something got lost in process. Review your work and see if you can find the missing term for the derivative.
2x+1 then?
How can it be 2x+1?
Except for the missing label, your result is fine. What leads you to believe it's not?
Try using the definition of the derivative to find the derivative of g(x)=x. Your result?
I don't know how to compute that but I will take your word for it. Thank you for helping.
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