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Mathematics 16 Online
OpenStudy (canada907cat):

Use the definition of the derivative f'(x)=lim h->0 f(x+h)-f(x)/h to find f'(x) where f(x)=x^2+x

OpenStudy (mathmale):

Your function is f(x) = x^2 + x. Please find \[f(x+ \Delta x)\]

OpenStudy (mathmale):

Then write out and simplify the difference quotient, \[\frac{ f(x+ \Delta x)-f(x) }{ \Delta x}\]

OpenStudy (mathmale):

Finally, let that delta x go to zero. The result is your derivative, f '(x).

OpenStudy (mathmale):

You can, of course, use "h" instead of "delta x."

OpenStudy (canada907cat):

would it be [(x+h)^2+(x+h)]-x^2+x/h?

OpenStudy (canada907cat):

would the answer be 2x?

OpenStudy (canada907cat):

@mathmale

OpenStudy (mathmale):

f '(x) = 2x plus an integer. Something got lost in process. Review your work and see if you can find the missing term for the derivative.

OpenStudy (canada907cat):

2x+1 then?

OpenStudy (canada907cat):

How can it be 2x+1?

OpenStudy (mathmale):

Except for the missing label, your result is fine. What leads you to believe it's not?

OpenStudy (mathmale):

Try using the definition of the derivative to find the derivative of g(x)=x. Your result?

OpenStudy (canada907cat):

I don't know how to compute that but I will take your word for it. Thank you for helping.

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