Is my work correct or would I have to do it differently since it's a one sided limit?

Find the limit if it exists. If it doesn’t exist, explain why.

Question

Is my work correct or would I have to do it differently since it's a one sided limit?

Find the limit if it exists. If it doesn’t exist, explain why.

thesmartone · Answer

$$\lim_{x \rightarrow 3^+}\left(\frac{\sqrt{x}-3}{x-9} \right)$$

$$\left(\frac{\sqrt{3}-3}{3-9} \right) = \boxed{\frac{\sqrt{3} - 3}{6}}$$

zepdrix · Answer

Is it maybe a typo?
Did they intend for this limit to approach 9 maybe?

zepdrix · Answer

As is, your work looks fine.

thesmartone · Answer

Nopee, it's 3 from the right

zzr0ck3r · Answer

then you  did it right

zzr0ck3r · Answer

Also sure it is not $\sqrt{x-3}$?

zzr0ck3r · Answer

then it would be undefined on the left....

thesmartone · Answer

Thanks, next one's coming up. :) The question is http://prntscr.com/cezda4

zepdrix · Answer

Maybe it gets more interesting in b)
lol :)

zzr0ck3r · Answer

weird...sometimes they just want to make sure you can notice the easy ones....I guess.

thesmartone · Answer

This question was continuous at 3 so yeah

It does get interesting at B, which will come in the next post xD