the reducing agent causes reduction but is itself oxidized
OpenStudy (photon336):
In ENGLISH: the reducing agent gives the other reactant electrons, causing it to be reduced. as a result, it loses electrons and is oxidized.
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OpenStudy (photon336):
so first step: write out the oxidation state of each of those reactants and products.
OpenStudy (photon336):
@NvidiaIntely
NvidiaIntely (nvidiaintely):
The answer is C, correct?
OpenStudy (photon336):
let's work towards the answer first
NvidiaIntely (nvidiaintely):
ok
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OpenStudy (photon336):
please write out oxidation states of C and O2
NvidiaIntely (nvidiaintely):
brb
NvidiaIntely (nvidiaintely):
The oxidation state of carbon can be very different, from -4 (in CH4) to +4.
OpenStudy (photon336):
alright so watch how I do it
NvidiaIntely (nvidiaintely):
okay.
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OpenStudy (photon336):
Free elements have oxidation states of zero
\[C^{0}(s)~+~ O^{0}_{2} \rightarrow CO_{2}\]
NvidiaIntely (nvidiaintely):
ok....
OpenStudy (photon336):
You should keep that in mind that will save you time
NvidiaIntely (nvidiaintely):
okay
OpenStudy (photon336):
In all compounds the sum of all oxidation states is zero unless there's an ion,
if there is an ion the sum of the oxidation states equals the ion.
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NvidiaIntely (nvidiaintely):
ok (I keep talking to let you know I am here)
OpenStudy (photon336):
Yeah so oxygen in a compound has an oxidation state of -2 because there are two oxygen atoms in CO2 we multiply -2*2 = -4.
so carbon must be +4
the sum of oxidation states = 0
so -4+4 = 0
\[CO_{2} \rightarrow Oxygen~=-2 ; \]
now
Carbon was 0 and is now +4
Oxygen was 0 and is now -2
NvidiaIntely (nvidiaintely):
Okay, I get it.
OpenStudy (photon336):
So based on what I said in the beginning go back and tell me what is the reducing agent. I wont just give you the answer.
NvidiaIntely (nvidiaintely):
Okay, let me see.
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NvidiaIntely (nvidiaintely):
Its C?
OpenStudy (photon336):
C as in Carbon or CO2?
NvidiaIntely (nvidiaintely):
CO2.
OpenStudy (photon336):
Why?
NvidiaIntely (nvidiaintely):
Okay, maybe I don't get it, let me read it a few times more.
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OpenStudy (photon336):
I'll be on for an other hour, so run through it step by step then get back to me.
NvidiaIntely (nvidiaintely):
Okay.
NvidiaIntely (nvidiaintely):
C
OpenStudy (photon336):
that was quite fast. the answer is Carbon C
NvidiaIntely (nvidiaintely):
Yeah that's what I mean't Carbon C.
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NvidiaIntely (nvidiaintely):
Thanks for you help!
OpenStudy (photon336):
So carbon goes from an oxidation state of 0 to +4
\[C^{0} \rightarrow C^{+4}~+4e^{-}\]
OpenStudy (photon336):
so carbon is giving its electrons to oxygen
OpenStudy (photon336):
so carbon is reducing oxygen. that's what the whole reducing agent thing means. it's a confusing term at first.
NvidiaIntely (nvidiaintely):
yeah, I got that now.
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