Find all vertical asymptotes of the following function.
\(\Large f(x) = \frac{\sqrt{x - 3}\sqrt{x^2 + 4}}{(x+4)(x-3)(x-5)}\)
So the domain is restricted to x > 3 because of sqrt(x - 3) So that means x = -4 cannot be a vertical asymptote. x = 5 is a vertical asymptote My question is, does x = 3 count as a vertical asymptote?
I believe it does but since the domain is restricted to x > 3 I'm not so sure :b
@mathmale
@pooja195 @procrastilate
Thank you for tagging others, giitter but there is no need to. I haven't tagged anyone because I have time and I don't want to bother people to help me. If the users want to help, they'll see my post and come and help. Just because they have a high SS doesn't mean they necessarily know the answer or want to help at the moment.
have you tried graphing the function?
You are right as to x=5 being an asymptote, and if the domain is strictly x>3 then x=3 cannot be an asymptote since 3 is not greater than 3.
wait a bit
x=3 will be a vertical asymptote
because lim x tends to 3+ f(x), check the limit
the denominator will be then sqrt(x-3) and hence x=3 will be a vertical aysmtote
@TheSmartOne
^ yea I think i am wrong then.
Check the definition, in any book, its given as x tends to a+ or a-, it never checks at x=a. , since the aymptote will never converge with the original function
Yes, x = 3 and x = 5 are both vertical asymptotes. Thanks! :) A definition that was given in class by the TA was if h(x) = f(x)/g(x) there will be a vertical asymptote when x = c for when g(c) = 0 but f(c) cannot equal to 0 also
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