Question

A bullet is fired into the air with an initial velocity of 1,200 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 2 seconds? (Neglect the resistance of air on the bullet. Round your answer to the nearest whole number.)
____ ft.
PLEASE HELP!

Answer 1

@pooja195

Answer 2

you've been waiting a while...

Answer 3

I have no idea about this one, it might take me a while to get an answer.

Answer 4

@mathmale A bullet is fired into the air with an initial velocity of 1,200 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 2 seconds? (Neglect the resistance of air on the bullet. Round your answer to the nearest whole number.)
____ ft.

Answer 5

First find the horizontal component of the initial velocity vector, then multiply that velocity by the given time.

Answer 6

@HolsterEmission Can you show me an example? Like a diagram maybe?

Answer 7

Sure:
Basic trig tells you that \(\cos\theta=\dfrac{\|\vec{v}_x\|}{\|\vec{v}\|}\), or \(\|\vec{v}_x\|=\|\vec{v}\|\cos\theta\). (Here \(\|\cdot\|\) means magnitude.)

You're given that \(\|\vec{v}\|=1200\) and \(\theta=45^\circ=\dfrac{\pi}{4}\text{ rad}\), so it's just a matter of plugging in these values.