Annoying, boring time waster problem with probably no good solution.
Evaluate \[\sigma(n)^{\tau(n)} \mod n\] \(\sigma(n)\) is the sum of divisors of n and \(\tau(n)\) is the number of divisors of n.
???? are those convolution sums?
this is definitely a waste of valuable brain cells. I think I've wasted plenty already lol
Yeah, they can be represented as convolutions but this isn't really haha.
https://en.wikipedia.org/wiki/Divisor_function or https://www.researchgate.net/publication/274184131_Evaluation_of_the_convolution_sums_l36mn_slsm_and_4l9mn_slsm
I seriously don't know
Not really sure why I thought this might be interesting, but since you have all the divisors added, when you raise it to the power of the number of divisor you're bound to get terms that are exactly equal to \(n\) itself based on the number of ways it combines, for instance, \[(1+2+3+6)^4\] contains the terms \(1*2*3\) several times which will get modded out.
that's what I was thinking too but wasn't really sure what it had to do with the problem
That paper's kind of interesting, defining these \(W_{a,b}(n)\) sums; do you know if they can be represented in terms of the Dirichlet convolution? Or what series actually makes them convolutions?
my internet's shotty, so if I don't reply don't worry
What is this stuff, this reminds me of some modular forms stuff but I have not dug too deep into it to know but it looks fun. Is there any particular motivation for why anyone would be interested in all these sums?
no I don't know what makes them convolutions, they just reminded me of them..
I'm more interested in learning something new if you got it rather than throw my self at some random garbage I made up, if you have any interesting math stuff you wanna share. What sorta math stuff are you into?
I don't know what the motivation is. It sounds complicated!!! :)
everything from basics to calculus & trig. :)
Well are you familiar with the Dirichlet convolution or the Riemann zeta function or not really into that sorta stuff yet haha
1 + 1 = 2.
My life motto. That's what I am familiar with. (:
no I kinda forgot. the process is complicated!!!!
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