Why are heat transfers associated with phase changes known as latent or "hidden" heats? Heat absorbed or released in a phase change is measured in kJ while temperature is measured in °C. The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. The enthalpy change values for pure substances tend to be small. The heat absorbed or released by a phase change does not cause a temperature change.
@jhonyy9 @phi @AloneS @sweetburger @welshfella @nincompoop @Nnesha @marvin456
A little research sorry, I forgot about these, but I read through some things all coming to the same theory. Let's see if I can explain it to you, and maybe you will see the correct choice:
Heat absorbed or released in a phase change is measured in kJ while temperature is measured in °C. (Measurement has no meaning to the phases stated.)
The enthalpy change values for pure substances tend to be small. It seems to be theoretically proven the value would be proven to become zero, not to a small value.
The heat absorbed or released by a phase change does not cause a temperature change. A temperature change does occur and result to zero.
The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. This seems to state the actual reason, to further express the achievement of getting the output to be zero. Adding the values together, for example.(-24) + 24 = 0.
What do you believe to be the answer now?
Let me see.
"add to zero" It results to zero, which is your answer. Sorry for not completely clarifying what I stated.
Is it D?
The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. Is the correct answer, glance at what I stated for this.
Ok.
I get it now, thanks!
Sure thing man.
Join our real-time social learning platform and learn together with your friends!