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Mathematics 14 Online
NvidiaIntely (nvidiaintely):

Why are heat transfers associated with phase changes known as latent or "hidden" heats? Heat absorbed or released in a phase change is measured in kJ while temperature is measured in °C. The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. The enthalpy change values for pure substances tend to be small. The heat absorbed or released by a phase change does not cause a temperature change.

NvidiaIntely (nvidiaintely):

@jhonyy9 @phi @AloneS @sweetburger @welshfella @nincompoop @Nnesha @marvin456

OpenStudy (vuriffy):

A little research sorry, I forgot about these, but I read through some things all coming to the same theory. Let's see if I can explain it to you, and maybe you will see the correct choice:

OpenStudy (vuriffy):

Heat absorbed or released in a phase change is measured in kJ while temperature is measured in °C. (Measurement has no meaning to the phases stated.)

OpenStudy (vuriffy):

The enthalpy change values for pure substances tend to be small. It seems to be theoretically proven the value would be proven to become zero, not to a small value.

OpenStudy (vuriffy):

The heat absorbed or released by a phase change does not cause a temperature change. A temperature change does occur and result to zero.

OpenStudy (vuriffy):

The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. This seems to state the actual reason, to further express the achievement of getting the output to be zero. Adding the values together, for example.(-24) + 24 = 0.

OpenStudy (vuriffy):

What do you believe to be the answer now?

NvidiaIntely (nvidiaintely):

Let me see.

OpenStudy (vuriffy):

"add to zero" It results to zero, which is your answer. Sorry for not completely clarifying what I stated.

NvidiaIntely (nvidiaintely):

Is it D?

OpenStudy (vuriffy):

The enthalpy of vaporization and enthalpy of condensation values for a substance add to zero. Is the correct answer, glance at what I stated for this.

NvidiaIntely (nvidiaintely):

Ok.

NvidiaIntely (nvidiaintely):

I get it now, thanks!

OpenStudy (vuriffy):

Sure thing man.

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