Question

I know this is a lot, but I can't put the equations in the right form with this computer.
f(x) = 3x + 2; g(x) = 3x - 5

Find f/g.
A. (f/g)(x) = Quantity three x minus five divided by three x plus two.; domain {x|x ≠ - Two over three. }
B. (f/g)(x) = Quantity three x plus two divided by three x minus five.; domain {x|x ≠ Five over three. }
C. (f/g)(x) = Quantity three x minus five divided by three x plus two; domain {x|x ≠ Five over three. }
D. (f/g)(x) = Quantity three x plus two divided by three x minus five; domain {x|x ≠ - Two over three. }

Answer 1

@jim_thompson5910 I have this question then one more after this. I know this is a mess.

Answer 2

similar thing, have to divide them
\[\large (f/g)(x) = \frac{ f(x) }{ g(x) } = \frac{ 3x + 2 }{ 3x-5 }\]

Answer 3

are you able to post a screenshot?

Answer 4

no :( I am sorry.. and I'll divide

Answer 5

@DanJS is correct. You just need to now find the domain. Set the denominator equal to zero and then solve for x. That will show you which value is going to be excluded from the domain.

Answer 6

Idk I'm not getting any of the answer options.

Answer 7

3x-5 = 0
solve for x to get x = ??

Answer 8

2?

Answer 9

add 5 to both sides first

Answer 10

then divide both sides by 3

Answer 11

-2?

Answer 12

3x-5 = 0

3x-5+5 = 0+5

3x = 5

x = ??? (it's not -2)

Answer 13

would the answer be B or C?

Answer 14

3x = 5

3x/3 = 5/3 ... divide both sides by 3

x = 5/3

Answer 15

To avoid division by zero errors, x = 5/3 must be excluded out of the domain

Answer 16

that's where I was horribly confused

Answer 17

C?

Answer 18

look carefully at what @DanJS posted

Answer 19

ohhh B

Answer 20

yes

Answer 21

thank you!

Answer 22

no problem