Two cars are initially (2.50+C) km apart on a straight road. If the cars are moving toward each other, car 1 with a speed of (5.40+A) m/s and car 2 with a speed of (7.20+B) m/s, how many seconds will it take before the cars meet? Round your answer to three significant figures.
A=8, B=1, C=9

Question

Two cars are initially (2.50+C) km apart on a straight road. If the cars are moving toward each other, car 1 with a speed of (5.40+A) m/s and car 2 with a speed of (7.20+B) m/s, how many seconds will it take before the cars meet? Round your answer to three significant figures.
A=8, B=1, C=9

simplixity · Answer

I have the answers to the equations, I just need help solving

danjs · Answer

The values give you two cars  11.50 km apart and moving 13.40 m/s and 8.20 m/s straight at each other...

simplixity · Answer

yeah, I got those

danjs · Answer

Distance = rate * time

Here the rate is the sum of both those velocities... 21.6 m/s

simplixity · Answer

okay so would I divide it by 11.50?

simplixity · Answer

wait, don't we have to convert km to m?

danjs · Answer

careful of the units,  the distance is in km and speeds are in meters/s

dist = rate * time
$$11500 ~m = 21.6~m/s ~~* t$$

simplixity · Answer

so $$11500 \div21.6$$ right?

danjs · Answer

yep