At what Celsius temperature will the numerical reading on the Fahrenheit thermometer be 51 ∘ less than that on the Celsius thermometer? Express your answer using two significant figures. I keep getting the wrong answer...
F to C: (C-32)/1.8 Problem interpretation: F = C-51
Therefore: C-32/1.8 = C-51?
C-32/1.8 is not degrees F.
Oh... :(
F = 1.8C + 32
I meant "F-32/1.8" my bad
C = (F - 32)/1.8
Yeah. That... ugh
You must put parentheses around F - 32.
Alright. How would I get only C in the equation, though?
You do a substitution. Start with: F = C - 51
F = 1.8C + 32, so where you see F, replace F with what F is equal to, which is 1.8C + 32. 1.8C + 32 = C - 51
Oh... is this going to turn into an equivalence problem?
... yup
Okay, so then I would end up with 0.8C = (-51-32)?
correct
Okay... I got this: 0.8C= -83 C = -103.75 degrees.
Correct.
And to cut down to two SF would make it ... I'm not sure how to do that actually
-103 rounds to -100, but that's three SF
Now let's check. Let's use our formula above to change -103.75 deg C to F F = 1.8C + 32 F = 1.8(-103.75) + 32 F = -186.75 + 32 F = -154.75 Sure enough, the number -154.75 51 less than -103.75
Yeah, but I don't know how to round sig figs... it wants two, but the only rounding I get is three sig figs. e-e
I see. You need 2 significant figures.
Although I'm really glad you helped me through the other parts. Thanks for that
I used a calculator and it gave me:\[1.0\times10^{2}\]
I think you can use scientific notation. -103.75 in scientific notation is -1.0375 * 10^2 Now write -1.0375 with 2 significant figures.
I thought 1.00 was the proper scientific notation?
Correct for the significant figure part, but remember it is negative.
1.00 has 3 sig figures. You must have 2, not 3, so use 1.0
Ah okay
... it said I got it wrong...
OH
ARGH
It says "check your signs." I mentioned above the answer is negative, so you need a negative sign before the 1.0
-1.0 * 10^2
Not so loud...
Ahem. * (*silent screaming*)
I'm sorry, I'm an idiot
If you were an idiot, you'd have given up. The fact that you're still at it until you understand it and get it right proves you are not.
At what Celsius temperature will the numerical reading on the Fahrenheit thermometer be 3-times more that on the Celsius thermometer?
Aw, thank you.
Set it up just like you did the first problem. First, write an equation with F and C that is just a translation of the sentence.
the numerical reading on the Fahrenheit thermometer be 3-times more that on the Celsius thermometer
So another substitution?
Yes, but we are still working on the step before the substitution.
What is "3-times more that on the Celsius thermometer", using C for the Celsius reading?
3x more is just times 3 right?
3 times the Celsius reading 3 times C
F = 3C and then combine that with the standard F conversion formula?
Ok. Now we use the conversion formula and we substitute.
So... 1.8C+32 = 3C
I just want to explain something before we substitute.
Oh. Yes?
There are two conversion formulas for F to C and for C to F. The are: C = (F - 32)/1.8 to convert from F to C F = 1.8C + 32 to convert from C to F How do we know which one to choose for the substitution step?
The F, because F=3C
F to C, I mean
GAH.
Oh, and I got this one right. Off by a couple digits but still correct
We go back to the question. The question is asking for the Celsius temperature. We need to solve for C, There is a solution for F also, but we were not asked to find it. Since we are solving only for C, we need to get rid of F and end up with only C in the equation. That is why we look for a conversion that has F = some expression in C. In this case, it is F = 1.8C + 32 After we substitute the conversion, we end up with an equation with just the variable C, so we can solve for C.
I got the answer right :)
At what Celsius temperature will the numerical reading on the Fahrenheit thermometer be 1/8 that on the Celsius thermometer?
Uh.. is this F = 1/8 C or F = 8 C?
One again, we now have F = 3C To get rid of F, we use F = 1.8C + 32 1.8C + 32 = 3C
F = (1/8)C
and now substitute the same way as before.
Alright, thank you :)
Mom's insulting me for being on here to get homework help...
Listen to your mom. Bye.
... I'm trying to work on my homework, though.
Join our real-time social learning platform and learn together with your friends!