Question

Using the table below, what is the change in enthalpy for the following reaction when all reactants and products are in the gaseous state?
Nitrogen Dioxide arrow Nitrogen Monoxide + Oxygen


113.0 kJ

255.0 kJ

56.5 kJ

−113.0 kJ

Answer 1

2NO2 -> 2NO + O2
delta Hf product - delta Hf reactant
(2 x delta Hf NO + delta Hf O2) - (2 x delta Hf NO2)
(2 x 90,37 + 0) - (2 x 33,85) =
113.04 kJ

Answer 2

ok

Answer 3

113 is the answer

Answer 4

Thanks Kevin!

Answer 5

u're welcome :)