Question

Using the table below, what is the change in enthalpy for the following reaction?
3CO (g) + 2Fe2O3 (s) arrow Fe(s) + 3CO2 (g)

−539.1 kJ

1754.7 kJ

539.1 kJ

795.2 kJ

Answer 1

ok

Answer 2

@Kevin

Answer 3

you dont tag me no more MAD -_-

Answer 4

i think 539.1 but idk if its right 100%

Answer 5

and am just kidding with you lol

Answer 6

Okay.
Btw I just saw you were here already xD

Answer 7

hahaha

Answer 8

lol hahahah

Answer 9

i would wait for kevin tho

Answer 10

yeah, I think so too.

Answer 11

where is the table?

Answer 12

Here, i forgot that :P

Answer 13

haha ok :D

Answer 14

I've calculated it twice, but still didn't meet the answer on your points :/

Answer 15

What do you mean?

Answer 16

You mean your answer is not listed?

Answer 17

yes

Answer 18

Is it alright if I write my own answer?

Answer 19

Yeah, show it to me.

Answer 20

Actually we should equalizes the chemical reaction like the question above, if I'm not equalizes it, the answer is listed then.

Answer 21

I will give you two kind of answers,

Here is the answer if you not equalizes the chemical reaction :

delta Hf product - delta Hf reactant --> the method still same with ur question b4
((0) + (3 * -393.5)) - ((3* -110.5) + (2 * -822.1)) =
795,2 kJ

And here is the ansewr if you equalizes the chemical reaction :

3CO + Fe2O3 = 2Fe + 3CO2

((2 * 0) + (3 * -393.5)) - ((3* -110.5) + (-822.1)) =
-26,9 kJ

Answer 22

Okay.

Answer 23

if it's multiple choice question, you can choose D
but I think the correct answer is -26,9 kJ :)

Answer 24

Okay, D was correct :)