Question

precal help needed: see attachment!

Answer 1

In a one-to-one function, given any y there is only one x that can be paired with the given y.

Answer 2

hmm, okay following..

Answer 3

Let me test them real quick.

Answer 4

The first one seems to keep getting one value for x.

Answer 5

so the first one would be considered a one-to-one function?

Answer 6

Yes.

Answer 7

okay, there should be two more that apply as well.

Answer 8

It seems the second one applies as well.

Answer 9

The third one does not apply.

Answer 10

It has two roots.

Answer 11

okay, i got two roots for the third one as well.

Answer 12

The fourth one seems to not apply with complex solutions of more than 1.

Answer 13

But the fourth does have only one real solution.

Answer 14

so these three are one-to-one functions?
\[f(x)=\frac{ x-1 }{ 3x+3}\]
\[f(x)=\sqrt{5x+9}\]
\[f(x)=3x^4+7x^3\]

Answer 15

The last has both more than 1 real and complex solutions, so I believe the fourth is also a one-to-one function.

Answer 16

The third one is f(x) = 1/2x^3 because of it only having ONE real solution.

Answer 17

so scratch out \[f(x)=3x^4+7x^3\]

Answer 18

Yes.

Answer 19

so A, B, D?

Answer 20

Yes, good job.