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Given the equation, -5|x + 1| = -10, the isolated absolute value equation would be |x + 1| = -15.
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i believe it would be Ix+1I=-5
-10 +5=-5
$$\huge -5|x + 1| = -10$$ Dividing both sides by -5 will isolate the absolute value: $$\huge \dfrac{-5|x + 1|}{-5}= \dfrac{-10}{-5}$$ $$\huge \dfrac{ \cancel{-5}|x + 1|}{\cancel{-5}}= 2$$ $$\huge |x + 1| = 2$$
@mitu12 the -5 in \(\Large -5|x + 1| = -10\) is being multiplied by the \(\Large |x + 1|\), so you cannot cancel it out by adding 5; addition can not undo multiplication, only division can.
With the exception that multiplication by 0 cannot be "undone" by division by 0 because division by 0 is undefined.
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