Question

Help Pleeeeease :3

Answer 1

\[\int\limits \frac{ 5x^2-20x+45 }{ (2x+1)(x-2)^2 }\]
Solve by expanding... So i got this far
\[\left( \frac{ A }{ (2x+1)} + \frac{ B }{ (x-2) } +\frac{ C }{ (x-2)^2 } \right) \times (2x+1)(x-2)^2\]
\[A(x-2)^2+B(2x+1)(x-2)+C(2x+1)\]
\[x=2 \rightarrow 5C = 25\rightarrow C=5\]
\[x=-\frac{ 1 }{ 2 } \rightarrow -\frac{ 5 }{ 2 }A=\frac{ 125 }{ 4 }+50+45 \rightarrow A=-\frac{ 101 }{ 2 }\]

I feel like messed up somewhere. Can someone check my work to see if I did everything correctly so far?

Answer 2

C=5 looks correct.
Hmm my A turned out differently.
Oh oh, you forgot to square the -5/2.

Answer 3

Oh right!
Now i got 101/5

Answer 4

Hm....
i got \[-\frac{ 5 }{ x-2 }+\frac{ 101 }{ 5 }\ln \left| 2x+1 \right|+ \frac{ 102 }{ 5 }\ln \left| x-2 \right|+C\]

But its wrong :/

Answer 5

Oh my goodness ! what are you learning ?LOL

Answer 6

Wait, actually. I've learned this! I think.. Haha. :)

Answer 7

@InstagramModel Its Calc 2. lol

Answer 8

Oh. Figured Lol

Answer 9

\(A(\dfrac{1}{2}-2)^2=5(\dfrac{1}{2})^2-20*(\dfrac{1}{2})+45\\A(-3/2)^2=5/4-10+45\\A9/4=5/4+35=145/4\\A =145/9\)

Answer 10

You are soooooooooo hot!

Answer 11

\[\large\rm 5x^2-20x+45=stuff\]Plugging in x=-1/2,\[\large\rm 5\left(-\frac12\right)^2-20\left(-\frac12\right)+45=A\left(-\frac{5}{2}\right)^2\]Solving for A should give you ... err at least this is what I'm coming up with,
\(\large\rm A=9\)

Answer 12

@Loser66 I think you plugged in x=1/2. It should be x= -1/2

Answer 13

Yes, my bad. :)

Answer 14

:P

Answer 15

@zepdrix Did you get
\[-\frac{ 5 }{ x-2 }+\frac{ 9 }{ 2 } \ln|2x+1|-2\ln|x-2| +C\] ?

Answer 16

I dunno, I didn't finish the problem.
Grr... hold on -_-

Answer 17

Oh... Sorry :/

Answer 18

Mmmmm yesssss good job.

Answer 19

Thanks :)

Answer 20

Just in case you wanted to see my work.
I'm not sure how you solved for B,
but I like to use some other easy peasy x value to find it.

Answer 21

I think I have my scanner settings are too high or something...
It takes like 3 minutes to scan a page,
and the detail is insane.

You can zoom in and see every little eraser and pencil mark XD haha

Answer 22

Haha, I see xD