im stuck...

Question

im stuck...

elusive · Answer

attachment

elusive · Answer

and.. this,.

mathstudent55 · Answer

The first one, move sqrt3 to the left side and factor by grouping.

mathstudent55 · Answer

The second one. Move sin x to the left side. Use the double angle formula on sin 2x, and factor.

elusive · Answer

I can't find any common variable. I'm sorry, math makes me feel retarded (bc i am)
@mathstudent55

elusive · Answer

attachment

jango_in_dtown · Answer

$$4\sin x \cos x-2 \sin x +2{\sqrt{3} \cos x- \sqrt{3}}$$

jango_in_dtown · Answer

$$= 2 \sin x (2 \cos x-1) +\sqrt{3} (2 \cos x-1)$$

jango_in_dtown · Answer

rest you proceed

jango_in_dtown · Answer

another one

jango_in_dtown · Answer

sin 2x= sin x implies 2 sin x cos x-sin x =0 implies sin x (2cos x-1)=0

jango_in_dtown · Answer

now solve for each factor to zero. never cancel out any factor

jango_in_dtown · Answer

@elusive

elusive · Answer

@jango_IN_DTOWN thank you, im still working on the first problem

elusive · Answer

cosx-1 ....

I can't apply the pyth identity because it's not squared. do I square it myself?

jango_in_dtown · Answer

which problem?

elusive · Answer

attachment

jango_in_dtown · Answer

In this problem you have to find x

jango_in_dtown · Answer

$$(2\cos x-1) (2 \sin x +\sqrt{3} )=0$$

jango_in_dtown · Answer

set each factor to zero and solve for x

elusive · Answer

thanks so much

jango_in_dtown · Answer

is there anything mentioned regarding the domain of x??

elusive · Answer

no.

mathstudent55 · Answer

Why is your first factor squared?

mathstudent55 · Answer

The answer is not the solution both factors have in common. The answer is all of the solutions of both factors. Also, if the domain is not restricted, then you need to find all values of x, not just the ones inside the interval [0, 2pi].