Question

Need Help?
17. The moon’s gravity is 1/6 that of the earth. If I jumped straight up in the air on the moon and on Earth, which place would I be able to jump higher?
a. The moon
b. The Earth
c. It would be the same height at each place
d. Not enough information

Answer 1

Lets say that you weighed 150 pounds on Earth. You would then weigh 24.9 pounds on the moon. Your muscles on the moon can exert the same amount of Newtons as they can on Earth. Knowing this information can you tell me what you think the answer is?

Answer 2

thank u! I already got thr answer its a But could you help me with another question I have most of It done I just need a little help @BlazeRyder

Answer 3

I can but I am not promising I can fully answer you =)

Answer 4

ok thanks

Answer 5

ok I needtosolve this I figured out what formula I need to use and what info is useful but how can I find the t in the equation if I don't have time yet

Answer 6

You would have to rearrange the equation. Do you know how to do that?

Answer 7

um kinda not really

Answer 8

is it this? 2x = 2vt - at^2

Answer 9

What does the ViT stand for in the equation. I know a stands for 9.81m/s and the T at the end of the equation stands for time.

Answer 10

Sorry, there should be a question mark at the end of the first sentence.... =)

Answer 11

Is this question in a Physics class?

Answer 12

actually in the problem A would be 23.6 because it given to us already. vi= 0m/s that's the initial velocity. and x= displacement= 88.3m/s so what I need is the t which is time

Answer 13

yeah its a question in physics

Answer 14

Okay, I am actually taking a Physics class this school year. Give me one sec, trying to figure it out.

Answer 15

ok thnks

Answer 16

I actually got help I'm not trying to be lazy. The equation and everything I got help from y physics teacher but now I don't know how to solve without the t given

Answer 17

I think the equation is wrong. In my Physics book the equation looks like this: \[\Delta Y=\frac{ 1 }{ 2 } \times a _{y} \times (\Delta t)^2\]

Answer 18

oh wow had not seen hat before. I go to connections academy i was taught to use these formulas

Answer 19

Then the equation would look like : \[T=\frac{ \sqrt{T \Delta Ya} }{ a }\]

Answer 20

oh ok well ill try and see if I can solve it..... but thank u though

Answer 21

This is how I solved it: \[T=\frac{ \sqrt{2 \times Deltay \times a} }{ a }\]

\[T=\frac{ \sqrt{2 \times 88.3 \times 23.6} }{ 23.6 }\]
\[T=\frac{ \sqrt{4,167.67} }{ 23.6 }\]
\[T=\frac{ 64.5574937556 }{23.6 }\]
\[T=2.73 seconds\]

Answer 22

oh my god thank u so much!

Answer 23

Your welcome! I had a similar question like this about 2 weeks and and I asked it here on OS in the physics category. I have learned with Physics they give you formulas and you can rearrange them to find answers different things. Also if you need help, go to Khan Academy. They have a lot of Physics videos. =)

Answer 24

ok thank u once again

Answer 25

No problem. Glad I could help!