Question

Find the discriminant and the number of real roots for this equation.

x2 + 2x + 8 = 0

A. 32; one real root
B. –28; no real roots
C. –28; one real root
D. 32; two real roots

Answer 1

do you know the formula for discriminant ?

Answer 2

D = b^2 -4ac

do you know the value of a,b and c ?

Answer 3

Isn't like b2-4ac

Answer 4

yes this is

Answer 5

A=1 b=2 c=8

Answer 6

yes this is correct

Answer 7

so just yous these value of a ,b and c and calculi the discriminant value

Answer 8

this is easy courage please

Answer 9

2^2-4(1)(8)
4-32 =28?

Answer 10

4-32 = ? not 28

Answer 11

It would be -28 ?

Answer 12

yes -28 so what is less than zero

do you know the case when the discriminant is less than zero what roots has the quadratic ?

Answer 13

do you learned it ?

Answer 14

It's would be one real ?

Answer 15

Or because it's negative it would have no real

Answer 16

no

there are 3 cases

discriminant let D

D > 0 there are two real ,different roots
D = 0 there are two real equal roots
D < 0 ?

Answer 17

I'm so confused

Answer 18

yes your last answer is right sure

Answer 19

so when the discriminant is less than zero so the quadratic have not real roots

ok. ?

Answer 20

Okay

Answer 21

Or because it's negative it would have no real

this your answer is right

hope do you understand it now

ok. ?

Answer 22

Yes I do
Thank you !

Answer 23

welcome

was my pleasure and anytime

good luck

bye bye