Question

Help PLS!

Answer 1

\[\int\limits \frac{ x^2-6x-9}{ (x-1)^2 (x^2+1) }\]
As my answer I got \[5\ln|x-1|+\frac{ 1 }{ x-1 }-\frac{ 5 }{ 2 }\ln|x^2+1|-3 \tan^{-1} (x)+C\]

But unfortunately its wrong...

Answer 2

Did you set up your partial fractions correctly?\[\large\rm \frac{x^2-6x-9}{(x-1)^2(x^2+1)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{Cx+D}{(x^2+1)}\]

Answer 3

Yea, Here is my work. It was too much to type out.

Answer 4

Oh you did it the other way...
expanding everything out... oh boy +_+

Answer 5

Yea... lol
I got stuck trying to do it the first way

Answer 6

Sec gonna try it the other way on paper :d

Answer 7

Cause I don't wanna check the expansion of those polynomials :P

Answer 8

Okie :3

Answer 9

Hmm ya I think expanding works out better -_- ugh

Answer 10

x(A+C-2D) not x(A+C+2D)

Answer 11

Ooooo. right right

Answer 12

Yep that was it. Thanks!
Ugh.... I mess up with small arithmetic calculations...

Answer 13

Noiceee