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Mathematics 17 Online
OpenStudy (simplixity):

Standing on the roof of a (42.0+A) m tall building, you throw a ball straight up with an initial speed of (14.5+B) m/s. If the ball misses the building on the way down, how long will it take from you threw the ball until it lands on the ground below? Give your answer in seconds and round the answer to three significant figures. A=9, B=8

OpenStudy (simplixity):

(42.0+A)= 51m

OpenStudy (simplixity):

(14.5+8)= 22.5 m/s

OpenStudy (simplixity):

I just need help with what equation to use..

jimthompson5910 (jim_thompson5910):

The equation you'll use is \[\Large y = -4.9x^2 + v*x + h\] y = height of object in meters at time x x = time in seconds v = initial speed h = initial height In this case, v = 22.5 h = 51 So we'll have this equation \[\Large y = -4.9x^2 + 22.5x + 51\] after you plug in the given info

jimthompson5910 (jim_thompson5910):

`how long will it take from you threw the ball until it lands on the ground below? ` set the height to zero then solve for x ie, replace y with 0 then isolate x

jimthompson5910 (jim_thompson5910):

you'll use the quadratic formula

OpenStudy (simplixity):

okay, hang on let me do the math.. is it okay if you check my answer after?

jimthompson5910 (jim_thompson5910):

sure that sounds like a good plan

OpenStudy (simplixity):

so this is how I set it up using the quadratic formula: \[\frac{-22.5 \pm \sqrt{22.5-4(-4.9)(51)} }{ 2(-4.9)}\]

jimthompson5910 (jim_thompson5910):

see attached

OpenStudy (simplixity):

so would then \[\frac{ -22.9 \pm \sqrt{1022.1} }{ -9.8}\] correct? or no

OpenStudy (simplixity):

oh wait I just saw your message

OpenStudy (simplixity):

so in the sqrt would be 1505.85?

jimthompson5910 (jim_thompson5910):

yes `1505.85` is under the square root when you simplify

OpenStudy (simplixity):

okay so what would I do next?

jimthompson5910 (jim_thompson5910):

so we'll have this \[\Large x = \frac{-22.5 \pm \sqrt{1505.85}}{-9.8}\]

jimthompson5910 (jim_thompson5910):

what is the square root of 1505.85 equal to?

OpenStudy (simplixity):

38.8053

OpenStudy (simplixity):

I think I know what to do

jimthompson5910 (jim_thompson5910):

ok tell me what two solutions you get

OpenStudy (simplixity):

I got -1.66 and 6.26 but I rounded them to the third sig fig

jimthompson5910 (jim_thompson5910):

Ignore -1.66 why? because x = -1.66 makes no sense. Recall that x is the time in seconds. We can't have a negative time value

jimthompson5910 (jim_thompson5910):

So the only solution is x = 6.26

OpenStudy (simplixity):

oh okay, thank you!

jimthompson5910 (jim_thompson5910):

you're welcome

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