Question

4/3s-3 9 years ago

Answer 1

please use parentheses bc. there not is clearly what is exactly the denominator or numerator of fractions

Answer 2

(4\[(4/3s)(-3)<(s+2/3)(-1/3)\]

Answer 3

It will be more easy if you just upload the picture :D

Answer 4

Ok I try

Answer 5

Here is an attachment in Microsoft word.

Answer 6

(4/3s)-3 < (s+2/3) -1/3
add 1/3 to each side
(5/3s) -3 < s+ 2/3
Subtract s from both sides
(2/3s) -3 < 2/3
Add 3 to both sides
2/3s < 11/3
Then multiply by the reciprocal
s< 11/2

Answer 7

1/3s** I'm sorry, I forgot to add the s to the 1/3

Answer 8

This is very long answer

Answer 9

\[\frac{ 4 }{ 3 }s - 3 < s + \frac{ 2 }{ 3 } - \frac{ 1 }{ 3s }\]
equate the denominator on the right side
\[\frac{ 4 }{ 3 }s < \frac{ 3s^2 +2s -1 }{ 3s }\]
multiply both of side with 3s
\[4s^2 - 9s < 3s^2 + 2s - 1\]
simplify the equation,
\[s^2-11s+1 < 0\]

Assume, it's \[s^2-11s+1 = 0\]
We can find s value using abc formula
\[s = \frac{ -(-11)\pm \sqrt{-11^2-4(1)(1)} }{ 2(1) }\]

we will get
\[s =\frac{ 11 }{ 2 }\pm \frac{ 3 }{ 2 }\sqrt{13}\]

Answer 10

Check its interval and we will get the final answer

\[\frac{ 11 }{ 3 }-\frac{ 3 }{ 2 } \sqrt{13}< s < \frac{ 11 }{ 3 }+\frac{ 3 }{ 2 } \sqrt{13}\]