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Mathematics 12 Online
OpenStudy (thatonegirl_):

Anyone wanna help with calc?

OpenStudy (legomyego180):

which calc?

OpenStudy (ash2326):

@Thatonegirl_ Do you need help?

OpenStudy (thatonegirl_):

if the function f defined by f(x)={cx+3, x<2 {3x^2-1, x>=2 is continuous everywhere on (-∞,∞), what is the value of f(1)?

OpenStudy (thatonegirl_):

Calc BC and yes please

OpenStudy (thatonegirl_):

I'm guessing i have to solve for c, but how?

OpenStudy (mathmale):

This function is defined with 2 parts: for x values to the left of 2 and for x values to the right of or equal to 2. In which interval does x=1 lie?

OpenStudy (thatonegirl_):

to the left

OpenStudy (mathmale):

OK. Which function pertains to x values to the left of 2? type it out.

OpenStudy (thatonegirl_):

cx+3

OpenStudy (mathmale):

Yes. You need to label that function. Would you mind doing so?

OpenStudy (thatonegirl_):

What do you mean label it?

OpenStudy (mathmale):

You have a name; this function has a name. The function's name is f(x). Write out this function, the one for x values to the left of 2.

OpenStudy (thatonegirl_):

ohh f(x)=cx+1 for x<2

OpenStudy (mathmale):

Cool. Perfect. Now replace x with '1' since we are evaluating f(1).

OpenStudy (thatonegirl_):

gotcha f(1)=c+1

OpenStudy (mathmale):

Since we don't have a value for c, your statement, above, is the best we can do. You're done.

OpenStudy (mathmale):

Just regard "c" as a constant.

OpenStudy (thatonegirl_):

okay so now what?

OpenStudy (mathmale):

Hold: You first defined that function as f(x) = cx+3. What happened to the 3? Start over; it'll only take a minute. Find f(1).

OpenStudy (thatonegirl_):

oops f(1)=c+3

OpenStudy (mathmale):

Right. We have no way to evaluate c, so just leave it there as a constant coeffficient of x. f(x)=cx+3 So your f(1)=c+3 is correct and complete.

OpenStudy (thatonegirl_):

Okay cool.

OpenStudy (mathmale):

Happy to be of help. Good luck to you!

OpenStudy (thatonegirl_):

Wait so what is the answer then??

OpenStudy (thatonegirl_):

my options are.. 7, 10, 11, 9, 8

OpenStudy (mathmale):

I've already told you that: Right. We have no way to evaluate c, so just leave it there as a constant coeffficient of x. f(x)=cx+3 So your f(1)=c+3 is correct and complete.

OpenStudy (mathmale):

You still have not provided any clue regarding how one would find the value of c. If the answer is contained in {7, 10, 11, 9, 8}, then something's missing from what you have shared with me.

OpenStudy (thatonegirl_):

OpenStudy (thatonegirl_):

this is everything :/ @mathmale

OpenStudy (thatonegirl_):

|dw:1473539721540:dw| so heres the second equation.. and the whole function is continuous so does this help somehow?

OpenStudy (irishboy123):

force the left and right sided limits at x = 2 to be equal.

OpenStudy (thatonegirl_):

nvm that graph should b part of a parabola lol and ohh okay thank you so much

OpenStudy (thatonegirl_):

cx+3=11 cx=8 c(2?)=8 c=4 @irishboy123

OpenStudy (irishboy123):

i got that too key thing is you agree with the idea, continuity.

OpenStudy (mathmale):

Sorry I missed the significance of "continuity" earlier. For the overall function to be continuous, the function defined on x<2 must equal the function defined on x equal to or greater than 2. Thus: Let x=2 and equate cx+3 to 3x^2 - 1.

OpenStudy (mathmale):

since x is no longer an unknown quantity, you now have all the info you need to solve for c. What is it?

OpenStudy (thatonegirl_):

The overall answer i got to be 7 with c=4 @mathmale thank you both so much :) @irishboy123

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