Question

PLEASE HELP ME SOLVE THIS INEQUALITY

8 |x + 3/4| < 2

Answer 1

\[\left| x+a \right|<b,-b<x+a<b\]

Answer 2

Uh...I think use the distribution property first...
8x+6<2?

Answer 3

8x=-4
Now divide 8 on both sides.
x=?

Answer 4

x would equal -.5 if that's the case, right?

Answer 5

\[\left| x+\frac{ 3 }{ 4 } \right|<\frac{ 2 }{ 8 }\]

Answer 6

\[\left| x+\frac{ 3 }{ 4 } \right|<\frac{ 1 }{ 4 }\]
?

Answer 7

im so lost tbh. i dont even know how to do this

Answer 8

\[-\frac{ 1 }{ 4 }<x+\frac{ 3 }{ 4 }<\frac{ 1 }{ 4 }\]
\[-\frac{ 1 }{ 4 } -\frac{ 3 }{ 4 }<x<\frac{ 1 }{ 4 }-\frac{ 3 }{ 4 }\]
?

Answer 9

umm...\[\frac{ -2 }{ 3 }\]

Answer 10

:D this is fun

Answer 11

\[\frac{ -1-3 }{ 4 }<x<\frac{ 1-3 }{ 4 }\]
\[\frac{ -4 }{ 4 }<x<\frac{ -2 }{ 4 }\]
\[-1<x<\frac{ -1 }{ 2}\]

Answer 12

or
if there is positive constant ,then you can distribute
\[\left| 8x+6 \right|<2\]
-2<8x+6<2
-2-6<8x<2-6
-8<8x<-4
divide each inequality by 8
?