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Mathematics 12 Online
OpenStudy (buckybarnes):

Check my work

OpenStudy (buckybarnes):

Find the area of the shaded region to the nearest 10th

OpenStudy (buckybarnes):

I got 13.7

OpenStudy (buckybarnes):

@sshayer

OpenStudy (buckybarnes):

@3mar

OpenStudy (3mar):

Yes

OpenStudy (3mar):

You know the area of the square = side length^2=8^2=64 Good?

OpenStudy (buckybarnes):

Yes

OpenStudy (3mar):

As this circle is drawn inside this square, then the its diameter equal to the square's side. And we know - and you - that the area of the circle is \[\pi(\frac{ diameter }{ 2 })^2\] So circle area will be \[\pi*(8/2)^2=16\pi\]

OpenStudy (3mar):

As this circle is drawn inside this square, then the its diameter equal to the square's side. And we know - and you - that the area of the circle is \[\pi(\frac{ diameter }{ 2 })^2\] So circle area will be \[\pi*(8/2)^2=16\pi\]

OpenStudy (3mar):

Next step and the last one ... Easily you can substract the area of the cirlce from the area of the square to get the shaded areas.

OpenStudy (3mar):

\[A _{shaded}=A _{\square}-A _{circle}\]

OpenStudy (buckybarnes):

I get 13.73451754256331

OpenStudy (3mar):

A_shaded=64-16pi=13.7143=13.7

OpenStudy (3mar):

If you face any difficulty, just tell me.'Hope that help you.

OpenStudy (buckybarnes):

So I was right?

OpenStudy (3mar):

And thanks of the medal!

OpenStudy (buckybarnes):

thank you for helping me

OpenStudy (3mar):

Yes, you are correct. Nice!

OpenStudy (3mar):

You are welcome!

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