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OpenStudy (3mar):
Yes
OpenStudy (3mar):
You know the area of the square = side length^2=8^2=64
Good?
OpenStudy (buckybarnes):
Yes
OpenStudy (3mar):
As this circle is drawn inside this square, then the its diameter equal to the square's side.
And we know - and you - that the area of the circle is \[\pi(\frac{ diameter }{ 2 })^2\]
So circle area will be \[\pi*(8/2)^2=16\pi\]
OpenStudy (3mar):
As this circle is drawn inside this square, then the its diameter equal to the square's side.
And we know - and you - that the area of the circle is \[\pi(\frac{ diameter }{ 2 })^2\]
So circle area will be \[\pi*(8/2)^2=16\pi\]
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OpenStudy (3mar):
Next step and the last one ...
Easily you can substract the area of the cirlce from the area of the square to get the shaded areas.
OpenStudy (3mar):
\[A _{shaded}=A _{\square}-A _{circle}\]
OpenStudy (buckybarnes):
I get 13.73451754256331
OpenStudy (3mar):
A_shaded=64-16pi=13.7143=13.7
OpenStudy (3mar):
If you face any difficulty, just tell me.'Hope that help you.
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