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Mathematics 26 Online
OpenStudy (legomyego180):

Hello

OpenStudy (legomyego180):

OpenStudy (legomyego180):

Not sure how to solve this.

jimthompson5910 (jim_thompson5910):

hint: cross product

OpenStudy (legomyego180):

is it simply a x b ?

jimthompson5910 (jim_thompson5910):

well that's the notation used, but there's more to it. Are you familiar with cross products with vectors?

OpenStudy (legomyego180):

yes, I use this shortcut where you write the components twice then do this weird thing.

OpenStudy (mathmale):

Yes, find the cross product of vectors a and b. The result will be perpendicular to both vectors a and b. Next, find the unit vector, vector u, stemming from that perpendicular vector. Proper notation for this unit vector is\[\frac{ u }{ |u| }\]

OpenStudy (mathmale):

Please show your work.

OpenStudy (mathmale):

Example: a unit vector in the direction of <1,2,3> is \[\frac{ <1,2,3> }{ \sqrt{1^2+2^2+3^2} }\]

OpenStudy (legomyego180):

It would be easier to show you than explain. i+3j+k j+2k 1 3 0 1 3 0 0 1 2 0 1 2 So I erase the last two rows so its 3 0 1 3 1 2 0 1 Then I cross: (3)(2)-(0)(1)=5 (0)(0)-(1)(2)=-2 (1)(1)-(3)(0)=-2 so my answer would be (5, -2, -2) Does this work?

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