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OpenStudy (loser66):
Where are you stuck?
OpenStudy (thephysicsman):
well, derivative with respect to x, this is a chain rule
OpenStudy (loser66):
ok, go ahead
OpenStudy (3mar):
This is the derivative if you want.
OpenStudy (queenechinose):
Why did you get a as the first derivative of the first term? I'm always confuse about that.
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OpenStudy (3mar):
Because we differentiate the (.....)^n and then differentiate what is in the (........)
So the differentiation of what in the (........) is (a)
OpenStudy (queenechinose):
I can't understand. I've got the same problem a while ago. Can you explain further? Like some examples? I'm sorry if I'm being pushy on this. This is the only part I can't understand and I've got loads of Practice problems with the same concept
OpenStudy (thephysicsman):
\[\frac{ d }{ dx }(ax+b)^{2} = 2(ax+b)*\frac{ du }{ dx }\]
\[u = ax+b | \frac{ du }{ dx } = ? \]
OpenStudy (queenechinose):
Yes I've got that part
OpenStudy (queenechinose):
It's a.
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