Question

A substance of unknown mass absorbs 1932 joules of energy, going from 26 to 42 degrees Celsius. If the specific heat of the substance is 4.29 J/g·°C, how much of the substance is present?

2.8 g

6.6 g

66.2 g

28 g

Answer 1

\[Q=m.C_p.(t_2-t_1)\]

Answer 2

1932=m.4.29(42-26)

m=28.15 gram

Answer 3

Okay.

Answer 4

Choice D ( the last one )

Answer 5

Yeah i know that.

Answer 6

But I have question for you, if I may know!!

Answer 7

Why do not you try yourself as you have your book and references?

Answer 8

I am doing it, just checking to see if its correct.
And I want a better understanding (:

Answer 9

You are welcome!