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Mathematics 58 Online
OpenStudy (itz_sid):

HELP PLS

OpenStudy (itz_sid):

Can someone please verify my work and answer please.

zepdrix (zepdrix):

-C=5 So... does that mean C=-5 ?

zepdrix (zepdrix):

Ya, that's your boo boo :O fix it

OpenStudy (itz_sid):

oopsies...

OpenStudy (seratul):

It does right? o.O

OpenStudy (itz_sid):

How about now?

zepdrix (zepdrix):

Why did you erase the negative on the C? You had -C=5, which was correct. Moving the negative to the other side gives us C=-5. C=5 doesn't translate to C=-5.

OpenStudy (itz_sid):

Oh yea. Oops. Accident D:

zepdrix (zepdrix):

And simplify your B further ya silly billy -_- -27/3 = -9

OpenStudy (seratul):

Sid, just saying, you have very nice handwritting.

OpenStudy (itz_sid):

LOL.

OpenStudy (itz_sid):

@Seratul Oh Thanks :)

OpenStudy (itz_sid):

So i simplified all the -27/3s to -9s. Is my final answer correct?

zepdrix (zepdrix):

We should fix the integral in the second to last step, ya? -5 in the numerator. And then something got mixed up integrating that term.

OpenStudy (itz_sid):

Or right. After integrating, that should have been a negative in my final answer, when i had made that mistake.

zepdrix (zepdrix):

\[\large\rm \int\limits\frac{-5}{(x-2)^2}dx\quad=\quad -5\int\limits (x-2)^{-2}dx\quad=\quad\frac{-5}{-1}(x-2)^{-1}\]

zepdrix (zepdrix):

No, not a negative. The 2.

OpenStudy (itz_sid):

Oh. Yea i see it.

OpenStudy (itz_sid):

How's that? :D

zepdrix (zepdrix):

yay good job

OpenStudy (itz_sid):

Yaaaaaay :D

OpenStudy (itz_sid):

@S4Sensitiveandshy Yea

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