HELP PLS
Can someone please verify my work and answer please.
-C=5 So... does that mean C=-5 ?
Ya, that's your boo boo :O fix it
oopsies...
It does right? o.O
How about now?
Why did you erase the negative on the C? You had -C=5, which was correct. Moving the negative to the other side gives us C=-5. C=5 doesn't translate to C=-5.
Oh yea. Oops. Accident D:
And simplify your B further ya silly billy -_- -27/3 = -9
Sid, just saying, you have very nice handwritting.
LOL.
@Seratul Oh Thanks :)
So i simplified all the -27/3s to -9s. Is my final answer correct?
We should fix the integral in the second to last step, ya? -5 in the numerator. And then something got mixed up integrating that term.
Or right. After integrating, that should have been a negative in my final answer, when i had made that mistake.
\[\large\rm \int\limits\frac{-5}{(x-2)^2}dx\quad=\quad -5\int\limits (x-2)^{-2}dx\quad=\quad\frac{-5}{-1}(x-2)^{-1}\]
No, not a negative. The 2.
Oh. Yea i see it.
How's that? :D
yay good job
Yaaaaaay :D
@S4Sensitiveandshy Yea
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