How do you move a stationary object?

Question

rayep12 · Answer

u push it, throw something at it

kainui · Answer

I would think to move it I change the velocity. So I have to apply an acceleration to it. But currently the object is not accelerating so I will have to change the acceleration. But it's change in its acceleration is not changing so I must change that too...

worldunseen · Answer

You apply a FORCE to it.

kainui · Answer

Yeah, but how do you apply a force to begin with?

itz_sid · Answer

Use the force of gravity lol

worldunseen · Answer

Multitude of ways. Gravity, applied force by various things and objects, elastic force, spring force, etc.

kainui · Answer

Yeah but how do you create a force to begin with?

worldunseen · Answer

@Kainui using energy

ganeshie8 · Answer

to change v, you must put a
to change a, you must put a'
...

kainui · Answer

I feel like I'm sorta stuck in an infinite regress like a zeno paradox kind of situation here, I don't think that 'energy' answers it because it's sorta tautological I feel.

kainui · Answer

yeah exactly @ganeshie8 understand what I am saying.

kainui · Answer

To clarify in case it's actually different:

To change v, you must put a. But putting a is changing the current a.
To change a, you must put a'. But putting a' is changing the current a'.
...

ganeshie8 · Answer

I think we surely have that paradox, but doesn't newton stop this at the level of acceleration by equating sum of forces to ma ?
$$\sum F = ma$$

ganeshie8 · Answer

(where "a" can vary over time..)

kainui · Answer

Yeah Newton's laws are only for inertial reference frames, with constant velocity I'm pretty sure but maybe not.

ganeshie8 · Answer

Yeah I'm considering only inertial reference frames

kainui · Answer

Well I don't know I feel like this means it's technically impossible to shift between different reference frames then.

ganeshie8 · Answer

Objects can have varying acceleration and this shouldn't cause any problem in shifting between inertial frames, right  ?

kainui · Answer

From Taylor's theorem we have:

$$x(t) = \sum_{n=0}^\infty  \left(\frac{d^n x}{dt^n} \right)_{t=0} \frac{t^n}{n!}$$

So it seems like really truly in general every position is only a sum of what happens after you know ALL the initial higher derivatives of position. They only become negligible because t is usually small and n! is really large I think.

That's my take on the situation so far, it's just an approximation.

imqwerty · Answer

Moving is a relative phenomena :p if u start moving then the stationary object is moving with respect to you without you applying any force on it

jiteshmeghwal9 · Answer

Telekinesis

baru · Answer

:P i was about to say zenos paradox...
Maybe quantum physics deals with this paradox?
something like momentum can only be imparted in finte discreet packets perhaps...?

when you say : it seems like really truly in general every position is only a sum of what happens after you know ALL the initial higher derivatives of position. They only become negligible because t is usually small....

i think this is an instance of a gap between a mathematical theory and the actual phenomenon... i think that the use of calculus is the approximation...