Question

Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph in the same direction as car A. At what time will car B pass car A?

Answer 1

@Kevin Got 1 for ya

Answer 2

This is what I have so far:
Let after t hours the distances D1 traveled by car A

=> D1 = 30 t

Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.

After (t - 1) hours, distance D2 traveled by car B

=> D2 = 40 (t - 1)

Answer 3

wait

Answer 4

let me solve this

Answer 5

gotta go

Answer 6

How many the distance between A and B start position?

Answer 7

Owh... I get it

Answer 8

30.t = 40(t - 1)
t = 4 hours

So it will be 9 + 4 = 1 PM

Answer 9

I'm back. I was on the phone :D
I multitasked and found out this:

Let after t hours the distances D1 traveled by car A

=> D1 = 30 t

Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.

After (t - 1) hours, distance D2 traveled by car B

=> D2 = 40 (t - 1)

When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2

=> 30 t = 40 (t - 1)

Solve the equation for t,

=> 30 t = 40t - 40

=> 10 t = 40

=> t = 4

=> Car B passes car A at = 9 + 4 = 13 pm.

Answer 10

That's a very good question. I need more question like this :D

Answer 11

OK! opening new q in a minute