Question

1 3
- - -
8 4

Answer 1

\[\frac{ 1 }{ 8 } -\frac{ 3 }{ 4 }\]

Answer 2

take L.C.M of 8 and 4

Answer 3

8?

Answer 4

@sshayer

Answer 5

\[\frac{ 3 }{ 4 }\times \frac{ 2 }{ 2 }=\frac{ 6 }{ 8 }\]

Answer 6

\[\frac{ 1 }{ 8 }-\frac{ 3 }{ 4 }=\frac{ 1 }{ 8 }-\frac{ 6 }{ 8 }=\frac{ 1-6 }{ 8 }=?\]

Answer 7

In summary: before you can add fractions, you must manipulate them so that all have the same denominator. 8 and 4 are not the same denominator.

However, if you multiply both numerator and denom. of (3/4) by 2, you get (6/8).

Then your problem becomes

\[\frac{ 1 }{ 8 }-\frac{ 6}{ 8 }\]

Answer 8

Evaluate this, please.