Question

whats wrong

Answer 1

you get it?

Answer 2

\(\sin ^2 x = 1 - \cos ^2 x\)

Answer 3

yes, that is what i was thinking, sin^2(x) + cos^2(x) = 1 , for the identity to use

1 - 2*cos^2(x) + cos^4(x)

\[\large 1 - 2* [1-\sin^2(x)]^2 + [1-\sin^2(x)]^4\]

then expand that out more for the end

Answer 4

Not quite sure what you did there..

Answer 5

It's telling me to use sin identity

Answer 6

i don't understand your last step..

Answer 7

as mentioned above sin^2x= 1-cos^2x
or if you want to use this identity \[\cos^2(x)=\frac{ 1+\cos(2x) }{ 2 }\] then it should be \[\frac{ 1-\cos^2(2x) }{ 4}= \frac{ 1-\frac{ 1+\cos(4x) }{ 2 } }{ 4 }\]doubl the angle

Answer 8

not sure howbto simplify

Answer 9

1. \(\sin ^4 x\) given

2. \((\sin^2 x)(\sin^2 x) \) product of two squares

3. \((1 - \cos^2 x)(1 - \cos^2 x) \) squared identity twice

4. \(1 - 2 \cos^2 x + \cos^4 x\) multiply the terms

5. \(1 - 2(1 - \sin^2 x) + (1 - \sin ^2 x)^2 \) squared identity

6. \(1 - 2 + 2 \sin^2 x + 1 - 2 \sin^2 x + \sin^4 x\) simplify

7. \(\sin ^4 x\) simplify

On line 5 it only mentions the squared identity once, so maybe it means this:

5. \(1 - 2(1 - \sin^2 x) + \cos^4 x\) squared identity

6. \(1 - 2 + 2 \sin^2 x + \cos^4 x\) simplify

7. \(\cos^4 x + 2\sin ^2 x - 1\) simplify

Answer 10

@mathstudent55
I have to rewrite it so I only have the first power of cosine