Functions. Help writing the formation correctly. See attached

Question

amy2012 · Answer

attachment

3mar · Answer

For the first box: just replace every x with x+1
$$H(x+1)=8(x+1)^2+8(x+1)-5$$

For the second one: replace every x with -x;
$$H(-x)=8(-x+1)^2+8(-x+1)$$

Any help ... any time

danjs · Answer

Yes @3mar is right on the first one  H(x + 1)

For the second, it asks for H(-x)
H(-x) = 8*(-x)^2 + 8*(-x) - 5
         =  8x^2 - 8x - 5

amy2012 · Answer

@3mar those are the answers I got and it said they were wrong

danjs · Answer

And they want you to expand them out,  put into a form ax^2 + bx + c

amy2012 · Answer

@DanJS the answer for the 2nd box you gave is correct...1st one is still wrong??

danjs · Answer

H(x+1)=8(x+1)^2+8(x+1)-5

 =  8 * (x^2 + 2x + 1) + (8x + 8) - 5
  =  8x^2 + 16x + 8 + 8x + 8 - 5
   =  8x^2 + 24x + 11

3mar · Answer

Sorry Amy2012 and DanJS
It is the fault of the equation editor.
again the second box
$$H(-x)=(-x)^2+8(-x)-5$$ 
then simplify
$$H(x)=x^2-8x-5$$

Sorry

danjs · Answer

it says to not used parenthesis, so i assume you have to do that, in form ax^2 + bx + c

3mar · Answer

Thanks, DanJS

danjs · Answer

Welcome, Does that go through good?
H(x + 1) = 8x^2 + 24x + 11

3mar · Answer

Correct, DanJS .